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leva [86]
3 years ago
5

Shana, who lives in Canada, and Pearl, who lives in Pennsylvania, were discussing the weather. Shana complained about the cold t

emperature of -20 C. Pearl, who lives in Pennsylvania, mentioned that her temperature was the opposite of Shana’s. Which is the correct way to represent “the opposite of Shana’s temperature is equal to Pearl’s”?
- -20 = 20
- (-20) = -20
- (20) = - 20
- -(20) = 20
Mathematics
1 answer:
mezya [45]3 years ago
6 0

Answer:

- -20 = 20


Step-by-step explanation:

The "opposite" here means we take the negative of -20 C.

So we can write - -20 which is equal to 20.

So the first option is correct, - -20 = 20.

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What is t÷5-4=9 what is t ??
Sophie [7]
Add 4 to boh sides
t/5+4-4=9+4
t/5+0=13
t/5=13
times 5/1 both sides
5t/5=5*13
1t=65

t=65
7 0
3 years ago
A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is an hourly wage of ​$20. Opt
sdas [7]

Answer:

40$

Step-by-step explanation:

they have

20$

5%

40hours

i=prt

multiplication of both

=40×20×5/100

=40$

the amount required at the week is 40$

7 0
3 years ago
Bob and Carl each rented the same kind of moving truck from EZ Move. There was a flat rental fee plus a charge per mile that the
dexar [7]

Answer:

ok so we can turn both of these into equations

Bob: 112.96 divided by 138=0.81855072463

so about 82 cents per mile

Carl: 142.78 divided by 209=0.68315789473

so about 68 cents per mile

so ya i am a little confused but heres what i got

7 0
3 years ago
Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]
Anit [1.1K]

Answer:

The answer is "\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}".

Step-by-step explanation:

\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}

Solve the L.H.S part:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]

After calculating the L.H.S part compare the value with R.H.S:

\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\

\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\

In equation (i) multiply by 3 and subtract by equation (iii):

\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to  c= - \frac{1}{2}

put the value of c in equation (i):

\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\

In equation (ii) multiply by 3 then subtract by equation (iv):

\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\

put the value of d in equation (iv):

\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2

The final answer is "\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}".

4 0
4 years ago
This question is Twelfth grade math please help fast .<br><br> 2x - (2y + 5) = 8
DENIUS [597]

You cannot solve this. TO solve both variables you need to have two equations. Please insert that equation in and I will solve this problem. :)

8 0
3 years ago
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