Answer:
(x, y) = (1, 1)
Step-by-step explanation:
Using the second equation to substitute for y in the first equation, we have ...
x = -2x +3
3x = 3 . . . . . . . add 2x
x = 1 . . . . . . . . .divide by 3
y = x = 1
The solution is (x, y) = (1, 1).
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If you have the graph, you can read the solution from it as the coordinates of the point where the lines cross.
Answer:

Step-by-step explanation:
3 envelopes having 2 red card
2 envelopes having 1 red card and 1 black card
1 envelope having 2 black cards
We are given that . An envelope is selected at random and a card is withdrawn and found to be red.
So, No. of ways of envelope having red card = 3+2 = 5
No. of required ways of envelope having 1 red card and 1 black card = 2
So, probability of getting an envelope having 1 red card and 1 black card = 
Hence The chance the other card is black is 
If x + y = 5 and 3x = 2 then what you
do is:
3x = 2 and since you want the variable by itself you’d divide by 3... giving you an answer of x = 2/3 BUT YOURE NOT DONE YET
so now you plug what x equals (2/3) into the equation x + y = 5:
2/3 + y = 5
to solve this you have to subtract each side by 2/3 so x = 5 - 2/3
(5/1 - 2/3.... to get like denominators multiply the nominator and the denominator for 5/1 by 3 giving you: 15/3 - 2/3 = 13/3)
your final answer would be 13/3
Answer:
25
Step-by-step explanation: