We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.

We know that formula for permutations is given as

On substituting the given values in the formula we get,


Therefore, there are 39270 ways in which prizes can be awarded.
Negative, Nonlinear,
I hope this helped:)
Answer:
(4.25, - 1.75)
Step-by-step explanation:
Under a reflection in the y- axis
a point (x, y ) → (- x, y ), thus
(- 4.25, - 1.75 ) → (4.25, - 1.75 ) ← original point
Answer:
y = (1/5)x² or y = x²/5
Step-by-step explanation:
We have the function f(x) = ax² and are given that the point (5,5) is on the parabola. We need to find 'a'. f(x) can be replaced with 'y', so we can rewrite the equation as...
y = ax²
We know that when x = 5, y = 5, so we have
5 = a(5²) now simplify...
5 = 25a
5/25 = a
1/5 = a, so our equation becomes
(1/5)x² or x²/5 (the expressions are equal)