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icang [17]
3 years ago
9

Which bicylic compounds are unstable at room temperature?

Chemistry
2 answers:
jek_recluse [69]3 years ago
8 0

Answer:

the compounds are:

Chlorine Trifluoride (CLF3)

Substance N (another way to call CLF3)

Azido Azide Azide (C2N14)

Explanation:

The instability of the C2N14 is beyond our handling capabilities. Minor tests of load and friction led to explosive decomposition.

This is the most explosive compound known, ironically two nitrogen atoms linked with a triple covalent bond is the most stable molecule, but in the case of Azido Azide Azide none of its 14 nitrogen atoms is linked by a triple bond, which makes it very unstable.

Substance N in 1930 was a new compound was discovered by Ruff and Krug in Germany. It was too volatile, so it was ignored, until a few years after it sparked interest in Nazi scientists. They named the compound substance n and it showed very particular properties:

· Boils at room temperature and produces toxic gas

· If the gas is ignited it burns at more than 2,400 degrees Celsius

· Explodes on contact with water

· If combined with coal it forms an explosive that detonates on contact with anything else

Seeing these properties and that substance n was so good at setting fire to things that were not flammable like glass or sand the Germans decided to use it.

It is a colorless gas or a highly reactive white solid with a sweet, suffocating odor. It is transported as a greenish-yellow liquid.

It is used in rocket boosters and in the processing of fuels for atomic reactors.

astraxan [27]3 years ago
8 0

Answer:

Explanation:

solution is stated in the attached document

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Answer:

Probably stop taking the prescribed durg and contact your pharmacist and your doctor that gave you your prescription asap.

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2 years ago
SeF6 1. Lewis Structure 2. Perspective drawing 3. Number of atoms bonded to central atom 4. Number of non-bonding electron pairs
Anarel [89]

The answer is- SF_{6} is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.

Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.

Determine the molecular geometry of SF_{6}.

  • Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
  • According to this theory, electrons are arranged around the central atom of the molecule in such a way that there is minimum electrostatic repulsion between these electrons.
  • Now, calculate the total number of valence electrons in SF_{6}.

Valence\ electrons\ in\ SF_{6}= Valence\ electrons\ in\ S +\ 6(Valence\ electrons\ in\ F)

Valence electrons of S = 6

Valence electrons of F = 7

Thus, the valence electrons in SF_{6} are-

Valence\ number\ of\ electrons\ in\ SF_{6} = (6) + 6(7) = 48\ electrons.

  • The Lewis structure of SF_{6} is - (Image attached).
  • In the structure, the number of atoms bonded to central atom (S) = 6.
  • Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
  • Electronic geometry in case of 6 bond pairs is octahedral.
  • Molecular geometry us also octahedral with bond angles 90°.
  • Central atom is sp3d2 hybridised.
  • SF_{6} is a non-polar molecule.

To learn more about Lewis structures visit:

brainly.com/question/12307841?referrer=searchResults

#SPJ4

7 0
1 year ago
Pls need help for answer now
yawa3891 [41]
The answer is 0.375 mol of silver chromate
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3 years ago
Calculate the molar concentration of the Cl⁻ ions in 0.92 M MnCl2(aq).
scZoUnD [109]
MnCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MnCl2 that dissolves.
MnCl2(s) --> Mn+(aq) + 2 Cl⁻(aq)
            [Cl⁻] = 0.92 mol MnCl2/1L × 2 mol Cl⁻ / 1 mol MnCl2 = 1.8 M
The answer to this question is [Cl⁻] = 1.8 M
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3 years ago
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