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Bond [772]
4 years ago
13

What is 80% as a ratio

Chemistry
1 answer:
Rashid [163]4 years ago
7 0

Answer:

4 : 5

Explanation:

80 percent can be written as:

80/100

Now we can reduce the above fraction to its lowest term as shown below

80/100 = 8/10

Divide both the numerator and denominator by 2.

8/10 = 4/5

Now, we can not divide further. So the ratio becomes 4 : 5

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You are investigating an organic compound. you discover the following: it contains no hydrogen atoms. what property do you expec
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the answer is C because it has no water there will be nothing to boil and odor has nothing to do with hydrogen

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3 years ago
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Concentrated hydrochloric acid is 36% (Weight/Volume) hydrochloric acid and has a density of 1.18 g.cm -3.
dezoksy [38]

The concentration refers to the amount of substance that is contained in solution.

<h3>What is the concentration?</h3>

The concentration refers to the amount of substance that is contained in solution. We can be able to obtain the concentration of the raw acid by the use of the relation;

Co = 10pd/M

M = molar mass of the acid

p = percentage of the acid

d = density of the acid

Co = 10 * 36 * 1.18/36.5

Co = 11.6 M

Using the dilution formula;

C1V1 = C2V2

10 * 11.6 = C2 * 1000

C2 = 10 * 11.6/1000

C2 = 0.116 M

Using again;

C1V1 = C2V2

0.116 * 5 = C2 * 20

C2 = 0.116 * 5 /20

C2 = 0.029 M

Learn more about concentration:brainly.com/question/10725862

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A cell needs to transport materials across the cell membrane. Which of the following best describes the type of transport shown
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Which condition is likely to result in the MOST competition?
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Metallic aluminum reacts with MnO2 at elevated temperatures to form manganese metal and aluminum oxide. A mixture of the two rea
Oksi-84 [34.3K]

Answer:

Explanation:

To find the theoretical yield of the equation. First identify the limiting reactant in a chemical equation.

Step 1: write out the equation and balance it.

Al+ 3mno2=3mn+ 2Alo3.

The limiting reactant is mn02 because it is not found in excess.

Step 2: convert the % to gram . All contain 67.2% mole and mno2 will be 100-67.2= 32.8

All=67.2÷100×290(total gram of the reactants)=194.88g

Mno2=32.8÷100×290g=94.12g.

Step 3:calculate the molar mass of mno2 and that of mn. The atomic mass of mn is 54.9380 and that of oxygen is 16.

Mno2=54.938+ (16)2=86.98g/mol.

Mn=54.938.

Step 4:

From your balanced equation , calculate mn.

94.12g mno2× (1mol mno2÷86.98(molarmass) of mno2×3 mol of mn/4molAl×54.938g of mn÷1mol of mn.

94.12g×1÷86.98g×3÷4×54.938÷1

=44.58g

6 0
3 years ago
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