Answer:
energy known as the latent heat of vaporization is required to break the hydrogen bonds. At 100 °C, 540 calories per gram of water are needed to convert one gram of liquid water to one gram of water vapour under normal pressure.
Explanation:energy known as the latent heat of vaporization is required to break the hydrogen bonds. At 100 °C, 540 calories per gram of water are needed to convert one gram of liquid water to one gram of water vapour under normal pressure.
The formula is Mn2+CO2= MnCO3
Answer:
The answer to your question is:
a) 0.023 mol of CdS
b) 0.12 mol of MoO3
c) 7.3 mol of AlPO4
Explanation:
a) CdS
MW = 112.4 + 32
= 144 g
144g ------------------ 1 mol
3.28g -------------- x
x = (3.28 x 1) / 144
x = 0.023 mol
b) MoO3
MW = 96 + 3(16) = 144 g
144g ------------------- 1 mol
17.5g ----------------- x
x = (17.5 x 1) / 144
x = 0.12 mol
c) AlPO4
MW = 27 + 31 + 4(16)
MW = 122 g
122 g ------------------ 1mol
890 g ------------------ x
x = (890 x 1) / 122
x = 7.3 mol of AlPO4
Divide 180kg and 90m3 and your density will be 2kg/m3
Answer:
Option "C" is the correct answer to the following question.
Explanation:
Given:
Pressure in an automobile tire (P) = 1.88 atm
Temperature (K) = 25°C = 273 + 25 = 298 Kelvin
New temperature (K1) = 37°C = 273 + 37 = 310 Kelvin
Find:
New pressure in an automobile tire (P1) = ?
Computation:
New pressure in an automobile tire (P1) = 1.9557
New pressure in an automobile tire (P1) = 1.96 (Approx)
