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SVETLANKA909090 [29]
2 years ago
11

Given: BC = 10 inches AC = inches m∠CBD = 60° m∠CAD = 90°

Mathematics
1 answer:
USPshnik [31]2 years ago
5 0
M∠CBD = 60°
BD = BC = 10 (radius)
m∠BCD = m∠BDC = 60°
equilateral triangle
CD = BC = 10

m∠CAD = 90°
AD = AC (radius)
m∠ACD = m∠ADC = 60°
AC = CDsin(45) ; pythagorus
= 10/sqrt(2) = 5sqrt(2)

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Suppose that two people standing 2 miles apart both see the burst from a fireworks display. After a period of​ time, the first p
Usimov [2.4K]

Answer: approximately 5148 feet directly north of point A

This is equivalent to 0.975 miles

==============================================================

Explanation:

Check out figure 1 (attached image below) to see how the drawing is set up.

Points A and B are separated by 2 miles, or 10560 feet. Use the conversion factor 1 mile = 5280 feet.

Because sound travels at roughly 1100 feet per second (assuming all of the conditions are right), this means that after x seconds, the sound wave has traveled a total distance of 1100x feet. This is the distance from A to C. Point C is the firework location.

The distance from B to C is 1100(x+6) feet because it takes 6 more seconds for the soundwave to travel from C to B, compared from C to A.

Note that triangle ABC is a right triangle. The 90 degree angle is at point A.

We can use the pythagorean theorem to solve for x

See figure 2 in the attached images to see the steps on solving for x. The numbers get quite big, though in the end x is fairly small. We end up with x = 4.68, which is approximate due to the 1100 figure being approximate.

This means the sound wave takes about 4.68 seconds to go from point C to point A.

With this x value, we can compute the expression 1100x to get

1100*x = 1100*4.68 = 5,148 feet

To convert this to miles, divide by 5280

(5148)/(5280) = 0.975

Therefore,

5148 feet = 0.975 miles

6 0
3 years ago
The average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed. What is
Anna35 [415]

Answer:

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

Step-by-step explanation:

We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.

Firstly, Let X = women's gestation period

The z score probability distribution for is given by;

         Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = average gestation period = 270 days

            \sigma = standard deviation = 9 days

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X \leq 261)

         P(X < 279) = P( \frac{ X - \mu}{\sigma} < \frac{279-270}{9} ) = P(Z < 1) = 0.84134

         P(X \leq 261) = P( \frac{ X - \mu}{\sigma} \leq \frac{261-270}{9} ) = P(Z \leq -1) = 1 - P(Z < 1)

                                                           = 1 - 0.84134 = 0.15866

<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>

Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

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