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Verizon [17]
2 years ago
12

What are the possible rational zeros of f(x) = x4 + 6x3 – 3x2 + 17x – 15?.

Mathematics
1 answer:
Keith_Richards [23]2 years ago
4 0
f(x) = x^4 + 6x^3-3x^2 + 17x-15\\\\15:\{\pm1;\ \pm3;\ \pm5;\ \pm15\}\\1:\{\pm1\}\\\\Answer:\boxed{\{\pm1;\ \pm3;\ \pm5;\ \pm15\}}
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PLS help i've been trying this for an hour i still don't get it
Tems11 [23]
I don’t know how to solve this but I think u have to use the fractions with the other numbers and multiply them then divide
4 0
3 years ago
A number is multiplied by 20, and that product is added to 5. The sum is equal to the product of 5 and 13.
liubo4ka [24]

Answer:

x = 3

Step-by-step explanation:

First, you will pick the first equation :

(x*20)

Then the next,

(x*20) + 5

Then the last equation,

(x*20) + 5 = 5*13

Then you solve

20x + 5 = 65

20x = 65 - 5

20x = 60

20x/20 = 60/20

x = 3

5 0
2 years ago
If two cards are randomly chosen from a standard deck, what is the probability that a 6 is chosen, replaced, and another 6 is ch
lord [1]

|\Omega|=52^2=2704\\ |A|=4^2=16\\\\ P(A)=\dfrac{16}{2704}\Rightarrow{\text{B}}

7 0
2 years ago
PLEASE HELP ASAP WILL MEDAL BRAINLIEST
Naddik [55]
Given
Present investment, P = 22000
APR, r = 0.0525
compounding time = 10 years
Future amount, A 

A. compounded annually
n=10*1=10
i=r=0.0525
A=P(1+i)^n
=22000(1+0.0525)^10
=36698.11

B. compounded quarterly
n=10*4=40
i=r/4=0.0525/4
A=P(1+i)^n
=22000*(1+0.0525/4)^40
=37063.29


Therefore, by compounding quarterly, she will get, at the end of 10 years investment, an additional amount of
37063.29-36698.11
=$365.18

5 0
2 years ago
Write an<br> algebraic expression for the following statement:<br> 9 times m increase by 6
raketka [301]

Answer:

9m+6

Step-by-step explanation:

9 times m is equivalent to 9m and if something is increasing by 6, its being added.

6 0
3 years ago
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