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Dvinal [7]
3 years ago
7

A square has a side length of 22 meters what is the area of the square

Mathematics
1 answer:
anzhelika [568]3 years ago
7 0

Answer:

A =484 m^2

Step-by-step explanation:

We find the area of a square by

A = s^2  where s is the side length

A = 22^2

A =484 m^2

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10 points someone help me please!?
Soloha48 [4]

Answer:

\large\boxed{b=\sqrt{95}}

Step-by-step explanation:

Use the Pyhagorean theorem:

leg^2+leg^2=hypotenuse^2

We have

leg=b,\ leg=7,\ hypotenuse=12

Substitute:

b^2+7^2=12^2

b^2+49=144       <em>subtract 49 from both sides</em>

b^2=95\to b=\sqrt{95}

7 0
3 years ago
Line segment AB has endpoint A locates at the origin. Line segment AB is longest when the coordinates of B are
Nana76 [90]

im pretty sure the answer is C


6 0
3 years ago
Solution of 34x+95=3(14x+9)
ch4aika [34]

Answer:

34 X + 95 is equal to 3 into bracket 14 x 1 + 9 (close

Step-by-step explanation:

it it is the for the algebra of class 10th not for 7 for all other classes

3 0
3 years ago
Find the value of (-8)(-3)(-2)(4).<br><br> A.17<br> B.-17<br> C.192<br> D.-192<br><br> helppp
julsineya [31]
Note: two negatives multiplied together = one positive answer
         one negative & one positive multiplied together = one negative answer
Multiply -8 and -3 together

-8(-3) = 24
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hope this helps

4 0
3 years ago
Read 2 more answers
Rhombus A has a base of 7 inches and an area of 35 square inches. Rhombus B has a base and height that are three times the base
STALIN [3.7K]
For rhombus A:
base = 7 in
area = 35 in²

Area of rhombus = b * h
⇒ 35 = 7 * h
⇒ h = 35/7
⇒ h = 5 in

Rhombus B:
height = 3*5 = 15 in
base = 7*3 = 21 in
Area = 15 * 21 = 315 in²

Area of rhombus B is 9 times area of rhombus A. When the dimensions are increased to 3 times the initial dimension, area became 9 times.

8 0
3 years ago
Read 2 more answers
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