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3 years ago

7

A square has a side length of 22 meters what is the area of the square

1 answer:

anzhelika [568]3 years ago

7 0

Answer:

A =484 m^2

Step-by-step explanation:

We find the area of a square by

A = s^2 where s is the side length

A = 22^2

A =484 m^2

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Inside a toy truck, there is a gear that rotates to (3, −8) when the steering wheel is turned to the left. What is the sine valu

Marianna [84]

This is the the concept of trigonometry, to get the sine value of the the function given we shall proceed as follows;
Using Pythagorean theorem, the hypotenuse of the triangle will be found as follows;
The side length will be 8 units since the y-coordinate is -8
The side width will be 3 units since the x- coordinate is 3
c^2=a^2+b^2
c^2=(3)^2+(-8)^2
c^2=9+64
c^2=73
c=sqrt(73)

Therefore the sine value will be:
sin x=3/sqrt(73)
multiply both numerator and denominator by sqrt(73) we get:
sin x=(3√73)/73

Therefore the answer is A]

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3 years ago

Identify the variable terms, constant terms, and coefficients for each expression.

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Answer:

ejnbn

Step-by-step explanation:

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3 years ago

How is your day?<br> My day is going great.

diamong [38]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

You are helping a coworker with the presentation and he has asked you to print out memos for him and a variety of color of paper

mr_godi [17]

He would need to print 10 memos

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3 years ago

Please answer the two questions!

shutvik [7]

Given:

The expressions are

(c) $\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3$

(d) $\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}$

To find:

The simplified form of the given expression.

Solution:

(c)

We have,

$\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3$

We know that, zero to the power of a non-zero number is always 1. So, $\left(\dfrac{2^4\times 3^6}{12^2}\right)^0=1$

$\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3=(1)^3$

$\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3=1$

Therefore, the value of the given expression is 1.

(d)

We have,

$\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}$

It can be written as

$\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13^3\times 1}{(65\times 49)^2}$

$\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13\times 13\times 13}{(65\times 49)(65\times 49)}$

$\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13}{(5\times 49)(5\times 49)}$

$\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13}{60025}$

$\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13}{60025}$

Therefore, the value of given expression is $\dfrac{13}{60025}$ .

7 0

2 years ago