Rhombus A has a base of 7 inches and an area of 35 square inches. Rhombus B has a base and height that are three times the base
and height of rhombus A. Find the area of rhombus B and compare it to the area of rhombus A. Explain.
2 answers:
For rhombus A:
base = 7 in
area = 35 in²
Area of rhombus = b * h
⇒ 35 = 7 * h
⇒ h = 35/7
⇒ h = 5 in
Rhombus B:
height = 3*5 = 15 in
base = 7*3 = 21 in
Area = 15 * 21 = 315 in²
Area
of rhombus B is 9 times area of rhombus A. When the dimensions are
increased to 3 times the initial dimension, area became 9 times.
Answer:
It must be B
Step-by-step explanation:
You might be interested in
28/4=7 Therefore 1/4 of 28 is 7
Answer:
idk
Step-by-step explanation:
K
i
n
k
y
Answer:
D
Step-by-step explanation:
Whenever 'to' is used we multiply the given values

Answer:
n=-2
Step-by-step explanation:
You do the reverse of -8 which is +8. -10+8=-2. n=-2
16 = 7 + 3x
So 3x + 7 = 16
Subtract 7 from both sides: 3x = 9
Divide both sides by 3: x = 3
Hope this helps!
Brainliest Please!