Answer:
Step-by-step explanation:
Given that X - the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.
Height of male pilot = 74.2 inches
We have to find the percentile
X = 74.2
Corresponding Z score = 74.2-72.6 = 1.6
P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%
i.e. only 5% are below him in height.
Thus the malepilot is in 5th percentile.
19-y because you are taking away y from 19
your answer is C 2/3 referring to over to the right 2 times and up 3 times
P(y)=4/15
P(r)= 3/14
(I’m assuming this is without replacement since you are the starburst, so there is one less of the total.)
