Once again similar traingles.
With same ratioes as before.
RS/RT = RV/RU=SV/TU = 1/2
X^2 + 12x = -6
x^2 + 12 x + 6^2 = -6 + 6^2
(x + 6)^2 = - 6 + 36
(x +6)^2 = 30
In the first step I had to add 6^2 = 36. The answer is option B. 36.
Answer:
56
Step-by-step explanation:
simple ratio: 7/95 = x/760
first, calculate 7/95 which is 0.0736
next, multiply that by 760, which would be 56
Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer:
<h2> 52 chickens</h2>
Step-by-step explanation:
Step one:'
given
we are told that the total number of animals is 169
the ratio of horses to chickens= 9:4
total ratio= 13
Required:
number of chickens
Applying part to all principle, let the number of chickens be x
4/13=x/169
cross multiply
4*169=13*x
divide both sides by 13
x=4*169/13
x=676/13
x=52
There are 52 chickens