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Nataly_w [17]
3 years ago
15

There were 436 tickets purchased for a major league baseball game. The general admission tickets cost ​$6.50 and the upper reser

ved tickets cost ​$8.00. The total amount of money spent was ​$3284.00. How many of each kind of ticket were​ purchased?
How many general admission tickets were​ purchased? ____
How many upper reserved tickets we purchased? ___
Mathematics
2 answers:
Nataly [62]3 years ago
8 0

Answer:

How many general admission tickets were​ purchased? __<u>136</u>__

How many upper reserved tickets we purchased? _<u>300</u>_

Step-by-step explanation:

Let the number of general tickets = g.

Let the number of reserved tickets = r.

6.5g + 8r = 3284

g + r = 436

     6.5g + 8r = 3284

(+)   -8g + -8r = -3488

--------------------------------

     -1.5g         = -204

g = 136

g + r = 436

136 + r = 436

r = 300

Answer:

How many general admission tickets were​ purchased? __<u>136</u>__

How many upper reserved tickets we purchased? _<u>300</u>_

Alina [70]3 years ago
4 0

Answer:

136 general admission tickets were purchased

300 upper reserved tickets were purchased

Step-by-step explanation:

This is a classic system of equations problem. Let the number of general admission tickets sold be g and the number of reserved tickets sold be r. We can write the following system of equations:

\begin{cases}6.50g+8.00r=3284,\\g+r=436\end{cases}

Multiply the second equation by -8 and add both equations to isolate g:

-8(g+r)=-8(436),\\-8g-8r=-3488,\\\begin{cases}6.50g+8.00r=3284,\\-8g-8r=-3488\end{cases},\\-1.5g=-204,\\g=\frac{-204}{-1.5}=\boxed{136}

Now substitute g=136 into g+r=436 to find the number of reserved tickets sold:

g+r=436,\\136+r=436,\\r=436-136=\boxed{300}

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Answer:

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Answer:

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Step-by-step explanation:

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This means that Q(12) = 0.5Q(0)

So

Q(t) = Q(0)e^{-rt}

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If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

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