Answer:
Part 1) The expression for the perimeter is
or 
Part 2) The perimeter when z = 15 ft. is 
Step-by-step explanation:
Part 1)
we have

Find the roots of the quadratic equation
Equate the equation to zero

Complete the square
Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient


Complete the square. Remember to balance the equation by adding the same constants to each side


Rewrite as perfect squares

-----> root with multiplicity 2
so
The area is equal to
![A=625(z-0.12)(z-0.12)=[25(z-0.12)][25(z-0.12)]=(25z-3)^{2}](https://tex.z-dn.net/?f=A%3D625%28z-0.12%29%28z-0.12%29%3D%5B25%28z-0.12%29%5D%5B25%28z-0.12%29%5D%3D%2825z-3%29%5E%7B2%7D)
The length side of the square is 
therefore
The perimeter is equal to



Part 2) Find the perimeter when z = 15 ft.
we have

substitute the value of z

We are given this equation :

We have to solve it for y, so we need to isolate y on the left side,
first we have 3x on the left side in addition, so when we take it to the right side we apply opposite operation that is subtract 3x

Next y is in multiplication with 5, so we apply opposite operation of multiplication that is division, so dividing right side by 5

Answer:
a) ![A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C1%26-1%261%5Cend%7Barray%7D%5Cright%5D)
![b=\left[\begin{array}{ccc}0\\1\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
b) 
c) ![A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%266%5Csqrt%7B2%7D%20%260%5C%5C%5Csqrt%7B3%7D%20%263%5Csqrt%7B3%7D%20%260%5C%5C2%26-16%260%5Cend%7Barray%7D%5Cright%5D)
![x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]](https://tex.z-dn.net/?f=x%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx_%7B1%7D%20%5C%5Cx_%7B2%7D%20%5C%5Cx_%7B3%7D%20%5Cend%7Barray%7D%5Cright%5D)
![b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-%5Csqrt%7B2%7D%20%5C%5C%5Csqrt%7B3%7D%20%5C%5C6%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
a) considering the equation:
Minimize 
(matrix A)
vector b
![b=\left[\begin{array}{ccc}0\\1\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
b) If Pxn is matrix B and p-vector d, we have:
minimize 
![Ax=\left[\begin{array}{ccc}0&-6&0\\-4&3&0\\1&8&0\end{array}\right]](https://tex.z-dn.net/?f=Ax%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-6%260%5C%5C-4%263%260%5C%5C1%268%260%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx_%7B1%7D%20%5C%5Cx_%7B2%7D%20%5C%5Cx_%7B3%7D%20%5Cend%7Barray%7D%5Cright%5D)
![b=\left[\begin{array}{ccc}-4\\1\\3\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%5C%5C1%5C%5C3%5Cend%7Barray%7D%5Cright%5D)
![Ax-b=\left[\begin{array}{ccc}-bx_{2}+4 \\-4x_{1}+3x_{2}-1 \\x_{1}+8x_{2}-3 \end{array}\right] =1](https://tex.z-dn.net/?f=Ax-b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-bx_%7B2%7D%2B4%20%5C%5C-4x_%7B1%7D%2B3x_%7B2%7D-1%20%20%5C%5Cx_%7B1%7D%2B8x_%7B2%7D-3%20%20%5Cend%7Barray%7D%5Cright%5D%20%3D1)

c) minimize 
in matrix:
![A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%266%5Csqrt%7B2%7D%20%260%5C%5C%5Csqrt%7B3%7D%20%263%5Csqrt%7B3%7D%20%260%5C%5C2%26-16%260%5Cend%7Barray%7D%5Cright%5D)
![x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]](https://tex.z-dn.net/?f=x%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx_%7B1%7D%20%5C%5Cx_%7B2%7D%20%5C%5Cx_%7B3%7D%20%5Cend%7Barray%7D%5Cright%5D)
![b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-%5Csqrt%7B2%7D%20%5C%5C%5Csqrt%7B3%7D%20%5C%5C6%5Cend%7Barray%7D%5Cright%5D)
Answer:
2/3
Step-by-step explanation: