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Nadya [2.5K]
2 years ago
6

X 12. Find the volume of the composite solid. Use 3.14 for . 5.5 ft Find the volume of the cone using the formula. ​

Mathematics
1 answer:
svetlana [45]2 years ago
6 0

Answer: 74.61 ft^3

Step-by-step explanation:

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The area of a square in square feet is
Sedaia [141]

Answer:

Part 1) The expression for the perimeter is P=4(25z-3) or  P=100z-12

Part 2) The perimeter when  z = 15 ft. is P=1,488\ ft

Step-by-step explanation:

Part 1)

we have

625z^{2}-150z+9

Find the roots of the quadratic equation

Equate the equation to zero

625z^{2}-150z+9=0

Complete the square

Group terms that contain the same variable, and move the constant to the opposite side of the equation

625z^{2}-150z=-9

Factor the leading coefficient  

625(z^{2}-(150/625)z)=-9

625(z^{2}-(6/25)z)=-9

Complete the square. Remember to balance the equation by adding the same constants to each side

625(z^{2}-(6/25)z+(36/2,500))=-9+(36/4)

625(z^{2}-(6/25)z+(36/2,500))=0

Rewrite as perfect squares

625(z-6/50)^{2}=0

z=6/50=0.12 -----> root with multiplicity 2

so

The area is equal to  

A=625(z-0.12)(z-0.12)=[25(z-0.12)][25(z-0.12)]=(25z-3)^{2}

The length side of the square is b=(25z-3)

therefore

The perimeter is equal to

P=4b

P=4(25z-3)

P=100z-12

Part 2) Find the perimeter when  z = 15 ft.

we have

P=100z-12

substitute the value of z

P=100(15)-12=1,488\ ft

4 0
3 years ago
Are anybody good at Math that could help me with all these answers and get them right and show your work and If you do it you ge
zepelin [54]
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3 0
3 years ago
Solve the equation 3x + 5y = 15 for y
Nana76 [90]

We are given this equation :

3x + 5y =15

We have to solve it for y, so we need to isolate y on the left side,

first we have 3x on the left side in addition, so when we take it to the right side we apply opposite operation that is subtract 3x

5y =15-3x

Next y is in multiplication with 5, so we apply opposite operation of multiplication that is division, so dividing right side by 5

y=\frac{15-3x}{5}

5 0
3 years ago
Read 2 more answers
Formulate the following problem as least squares problems. For each problem, give a matrixA and a vector b such that the problem
hammer [34]

Answer:

a) A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]

b=\left[\begin{array}{ccc}0\\1\end{array}\right]

b) ||Ax-b||^{2} =(-bx_{2}+4)^{2}  (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}

c) A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]

x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]

b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]

Step-by-step explanation:

a) considering the equation:

Minimize x_{1}^{2}  +2x_{2}x^{2}  +3x_{3}^{2}+(x_{1}   -x_{2} +x_{3} -1)^{2} +(-x_{1} -4x_{2} +2)^{2}

A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right] (matrix A)

vector b

b=\left[\begin{array}{ccc}0\\1\end{array}\right]

b) If Pxn is matrix B and p-vector d, we have:

minimize (-6x_{2}+4)^{2}  +(-4x_{1} +3x_{2} -1)+(x_{1} +8x_{2} -3)^{2}

Ax=\left[\begin{array}{ccc}0&-6&0\\-4&3&0\\1&8&0\end{array}\right]

\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]

b=\left[\begin{array}{ccc}-4\\1\\3\end{array}\right]

Ax-b=\left[\begin{array}{ccc}-bx_{2}+4 \\-4x_{1}+3x_{2}-1  \\x_{1}+8x_{2}-3  \end{array}\right] =1

||Ax-b||^{2} =(-bx_{2}+4)^{2}  (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}

c) minimize 2(-bx_{2}+4)^{2}  +3(-4x_{1} +3x_{2} -1)^{2} +4(x_{1} -x_{2} -3)^{2} -(6\sqrt{2}x_{2}  +4\sqrt{2} )^{2} +(-4\sqrt{3} x_{1} +3\sqrt{3}x_{2}  -\sqrt{3})^{2}  +(2x_{1} -16x_{2} -6)^{2}

in matrix:

A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]

x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]

b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]

6 0
3 years ago
(IXL Question) What is the slope?
bonufazy [111]

Answer:

2/3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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