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baherus [9]
3 years ago
14

Which points are the foci of the ellipse?

Mathematics
2 answers:
Mazyrski [523]3 years ago
7 0

The foci need to be equal distances from the center of the eclipse.

See the attached picture. I marked off all the points that were given as choice and from this you can see that that (-5,-4) and  (-5,2) are both 3 units away from the center.

The answer is: (-5,-4) and  (-5,2)

Margaret [11]3 years ago
6 0

Answer:

c on edge

Step-by-step explanation:

finished the test

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Help please due soon
ANEK [815]

Answer: c=24

Step-by-step explanation: 15×3=45. 8×3=24. Just multiply both the numerator and denominator by 3.

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3 years ago
Read 2 more answers
3 squared 7=7 1/3 simplification
anzhelika [568]
Error! Because that does not make any sense
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3 years ago
Use the stem and leaf plot graph to answer the question.
kogti [31]
<h3>Answer:   13 days</h3>

====================================================

Explanation:

Count the number of leaves marked in green.

  1. Row One: 2 leaves (1 and 8)
  2. Row Two: 3 leaves (3, 6, and 9)
  3. Row Three: 5 leaves (2, 3, 4, 6, 7)
  4. Row Four: 3 leaves (1, 6, and 8)

There are 2+3+5+3 = 13 leaves total. This represents tickets were sold on 13 days.

Each stem and leaf combines to form a different ticket count. For instance, the stem of 1 and leaf of 8 combine to get the value 18. So 18 tickets were sold on that particular day.

7 0
2 years ago
What is the factorization of the trinomial below?
lidiya [134]

Answer:

B)

Step-by-step explanation:

4 0
3 years ago
Ten samples of a process measuring the number of returns per 100 receipts were taken for a local retail store. The number of ret
Tatiana [17]

Answer:

0.0273

Step-by-step explanation:

np  n

10  100

9    100

11   100

7    100

3   100

12  100

8   100

4    100

6    100

11   100

pbar=sumnp/sumn

pbar=10+9+11+7+3+12+8+4+6+11/10+10+10+10+10+10+10+10+10+10

pbar=81/1000

pbar=0.081

nbar=sumn/k=1000/10=100

Standard deviation for pbar chart=\sqrt{\frac{pbar(1-pbar)}{nbar} }

Standard deviation for pbar chart=\sqrt{\frac{0.081(0.919)}{100} }

Standard deviation for pbar chart=\sqrt{\frac{0.0744}{100} }

Standard deviation for pbar chart=\sqrt{0.0007444 }

Standard deviation for p-chart=0.0273

3 0
3 years ago
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