Both parents' genotypes are Bb (brown blue)
the punnet square would be
BB(kid one) Bb(kid two) Bb(kid three) bb(kid four)
kid one will be homozygous for brown eyes. kid two and three will be heterozygous for brown eyes. kid four will be homozygous for blue eyes
in other words, 75% will have brown eyes. 25% will have blue eyes
Microscopes allowed scientists to observe Prokaryotic cells which make up Bacteria and Archaea. These cells are small and contain no membrane- bound organelles. It allowed them to observe Eukaryotic cells with a nucleus and membrane-bound organelles that perform different life functions.
Answer:
If both parents do not have sickle-cell anemia, than the possibility is low.
Explanation:
If both parents have the sickle-cell trait, their offspring has a 25 percent chance of getting sickle cell anemia and a 50 percent risk of them having sickle cell trait. Meanwhile, there is also a 25 percent chance of the child not getting it at all.
If one parent has sickle cell anemia and the other has sickle cell trait, then their offspring with have a 50 percent chance of getting sickle cell anemia and a 50 percent chance of getting a sickle cell trait.
When both parents have sickle cell anemia, their child will definitely have it.
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