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3 years ago

9

What is the area of a rectangle with a base of 10 inches and an altitude of 12 inches?

1 answer:

WARRIOR [948]3 years ago

7 0

First your gonna take the inches (10) and multiply that by the altitude (12) and that’s the area
AREA: multiply

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3(m - n + 2) + 6 - m

julia-pushkina [17]

Step-by-step explanation:

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2 years ago

Graph x=-4 how is that line placed on the coordinate system

Vesna [10]

A vertical line on the value x = -4

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3 years ago

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The cost of 11 dvds and 7 cds is 172.50 and the cost of 10 dvds and 7 cds is 155.80. How much does a cd and dvd cost?

AleksandrR [38]

Answer:

The question has a mistake

Step-by-step explanation:

11d+7c= 172.5

10d+7c= 155.8

By subtraction;

1d+ 0c = 16.7

1d = 16.7

11×16.7+7c=172.5

7c = 172.5-11*16.7

You will get a negative answer yet the cost cannot be negative.

5 0

2 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

2 years ago

Read 2 more answers

On a website, listeners rate music from 1 star to 5 stars. One song was rated 1 star by 3.5% of the listeners. There were 49 lis

defon

Answer:

1400

Step-by-step explanation:

3.5% of listeners rated the song as 1 star

49 listeners rated the song as 1 star

49 listeners = 3.5% of listeners

we want to find 100% of listeners. we can do this by multiplying both sides of the equation by 100/3.5, getting one side to 100% and the other to what it is equal to

49 * 100/3.5 listeners = 100% of listeners = 1400

3 0

2 years ago