Answer:
The process is adiabatic because there no heat transfer into the system or out of the system in that there is only one system involved in this process that is air.
The temperature of the air mass when it has risen is
Explanation:
From the question we are told that
The atmospheric pressure is ![P_a = 1.01 *10^{5} \ Pa](https://tex.z-dn.net/?f=P_a%20%20%3D%201.01%20%2A10%5E%7B5%7D%20%5C%20Pa)
The temperature heated to
The new atmospheric pressure is ![P_a__{n}} = 8.0 * 10^{4} \ Pa](https://tex.z-dn.net/?f=P_a__%7Bn%7D%7D%20%20%3D%20%208.0%20%2A%2010%5E%7B4%7D%20%5C%20Pa)
The value of g is ![g = 1.40](https://tex.z-dn.net/?f=g%20%3D%20%201.40)
The rate of cooling is ![r = \frac{1}{100} \ ^oC/m](https://tex.z-dn.net/?f=r%20%3D%20%20%5Cfrac%7B1%7D%7B100%7D%20%20%5C%20%5EoC%2Fm)
The adiabatic relation for this process is mathematically represented as
![P^{1- g}_{initial} T^{g}_{initial} = P^{1-g} _{final} T^{g}_{final}](https://tex.z-dn.net/?f=P%5E%7B1-%20g%7D_%7Binitial%7D%20T%5E%7Bg%7D_%7Binitial%7D%20%3D%20%20P%5E%7B1-g%7D%20_%7Bfinal%7D%20T%5E%7Bg%7D_%7Bfinal%7D)
Now
,
,
, ![T_{final} = ?](https://tex.z-dn.net/?f=T_%7Bfinal%7D%20%20%3D%20%3F)
substituting value
![(1.01*10^{5})^{1-1.40} * (305) ^{1.40} = (8.0*10^{4})^{1-1.40} * T_{final} ^{1.40}](https://tex.z-dn.net/?f=%281.01%2A10%5E%7B5%7D%29%5E%7B1-1.40%7D%20%2A%20%28305%29%20%5E%7B1.40%7D%20%3D%20%288.0%2A10%5E%7B4%7D%29%5E%7B1-1.40%7D%20%2A%20T_%7Bfinal%7D%20%5E%7B1.40%7D)
![T_{final} ^{1.40} = 2646.7](https://tex.z-dn.net/?f=T_%7Bfinal%7D%20%5E%7B1.40%7D%20%20%3D%20%202646.7)
=>
Answer:
2) 25.0mL aliquots of the solution in problem 1 are titrated with EDTA to the calmagite end point. A blank containing a small measured amount of Mg2+ requires 2.12mL of the EDTA to reach the end point. An aliquot to which the same amount of Mg2+ is added requires 25.88mL of the EDTA to reach the end point.
a. How many mL of EDTA are needed to titrate the Ca2+ ion in the aliquot?
b. How many moles of EDTA are there in the volume obtained in a.?
c. What is the molarity of the EDTA solution?
Explanation:
Given that;
Volume of aliquot = 25mL
Blank reading = 2.12mL
2a)
Volume of EDTA used for Ca²⁺ ion
25.88mL - 2.12mL = 23.76mL
Therefore mL of EDTA needed to titrate the Ca²⁺ ion in the aliquot is 23.76mL
2b)
Molarity of Ca²⁺ ion is 0.0172M
Mole of EDTA =
![=\frac{0.0172 moles}{1l} \times (25mL) \times \frac{1L}{1000mL} \\\\=0.00043moles](https://tex.z-dn.net/?f=%3D%5Cfrac%7B0.0172%20moles%7D%7B1l%7D%20%5Ctimes%20%2825mL%29%20%5Ctimes%20%5Cfrac%7B1L%7D%7B1000mL%7D%20%5C%5C%5C%5C%3D0.00043moles)
2c)
Molarity of EDTA = mole of EDTA / Vol. of EDTA
![=(\frac{0.00043mole}{23.76mL} )\times \frac{1000mL}{1L} \\\\=0.0180M](https://tex.z-dn.net/?f=%3D%28%5Cfrac%7B0.00043mole%7D%7B23.76mL%7D%20%29%5Ctimes%20%5Cfrac%7B1000mL%7D%7B1L%7D%20%5C%5C%5C%5C%3D0.0180M)
Answer:
transitive physicsif something conducts heat or electricity, heat or electricity can move through it.
Explanation:
This is most likely "-100 kj/mol, spontaneous," but the question is difficult to read