Question

A generic gas, x, is placed in a sealed glass jar and decomposes to form gaseous y and solid z. 2x(g)↽−−⇀y(g)+z(s) how are these equilibrium quantities affected by the initial amount of x(g) placed in the container? assume constant temperature.

Answer 1

Formation of Y and Z directly depends on initial amount of X present.

Further Explanation:

Le Chatelier’s principle:

This states that any change in pressure, temperature or concentration in any reaction that is present in equilibrium tends to shift equilibrium in such direction that reverses the effect of changed quantity in reaction.

Given reaction occurs as follows:

$2\text{X(g)}\rightleftharpoons\text{Y(g)}+\text{Z(g)}$

According to this reaction, two moles of X decompose to form one mole of Y and one mole of Z.

Amounts of Y and Z formed during the given reaction depend on initial amount of X present. More the amount of X, higher will be formation of products Y and Z and vice-versa. So if amount of X is increased, equilibrium will tend to shift in direction that reverses this effect. This is done only by increased consumption of X that results in more formation of products. Therefore more amounts of Y and Z are formed if initial amount of X is increased and formation of Y and Z decreases if initial amount of X is decreased.

Learn more:

• Calculation of equilibrium constant of pure water at 25°c: brainly.com/question/3467841
• Complete equation for the dissociation of  (aq): brainly.com/question/5425813

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Chemical Equilibrium

Keywords: Le Chatelier’s principle, equilibrium, shift, direction, X, Y, Z, 2X, pressure, temperature, concentration, consumption, increase, decrease, two moles, one mole.

Answer 2

Answer: the equilibrium will be displaced to the right leading an increase on the quantities of y(g) and z(s).

Justification:

According to the rules of equilibrium, based on Le Chatellier's priciple, any change in a system in equilibrium will be tried to be compensated to restablish the equilibrium

The higher the amount, and so the concentration, of X(g), the more will the forward reaction proceed leading to an increase on the concentration of the products y(g) and z (s). Look that that will also be accompanied by a decreasing on the pressure, since 2 molecules of the gas X(g) are converted into 1 molecule of the gas y(g).