What volume is needed to make a 2.45 M solution of KCl using 0.50 mol of KCl
1 answer:
Answer:
Explanation:
91.4
grams
Explanation:
C
=
m
o
l
v
o
l
u
m
e
2.45
M
=
m
o
l
0.5
L
2.45
M
⋅
0.5
L
=
m
o
l
m
o
l
=
1.225
Convert no. of moles to grams using the atomic mass of K + Cl
1.225
m
o
l
⋅
(
39.1
+
35.5
)
g
m
o
l
1.225
m
o
l
⋅
74.6
g
m
o
l
=
1.225
⋅
74.6
g
=
91.4
g
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