Answer:
3.0 g daily dose
Explanation:
First of all, the given dose is measured in milligrams per kilogram of body and the mass of this patient is given in pounds. This means we have to begin this problem by converting the units.
Convert the mass into kilograms:
Knowing that the dose is 15.0 mg per kilogram of body, one dose is equal to:
This is a single dose. If we wish to calculate the daily dose, since it's used twice, we get:
With a process called Fission. This generates heat to produce steam.
Answer:
Explanation:
So we take the given quotient:
ρ=176⋅g4⋅cm×4⋅cm×4⋅cm = 176⋅g64⋅cm3 = ??g⋅cm−3.
Would the cube float or sink in water? Why
Answer: 1082 g of carbon dioxide are produced for every 350 grams of octane reacted in the engine
Explanation:
To calculate the moles :
According to stoichiometry :
As 2 moles of octane give = 16 moles of
Thus 3.07 moles of octane will give = of
Mass of
Thus 1082 g of carbon dioxide are produced for every 350 grams of octane reacted in the engine
Answer:
See explanation
Explanation:
-0.7ev = -13.6/n^2
n= 4
4--->1
4--->3, 3---> 2, 2--->1
E4-E1= -13.36(1/4^2 - 1/1^2) = 12.53 eV
E4-E3 = -13.36 (1/4^2 - 1/3^2) = 0.65 ev
E3-E2 = -13.36 (1/3^2 - 1/2^2) = 1.86 eV
E2- E1 = -13.6 ( 1/2^2 - 1/1^2) = 10.02 ev
a)
λ= 6.6 × 10^-34 × 3 × 10^8/12.53 × 1.6 × 10^-19
λ= 19.8 × 10^-26/20.048 ×10^-19
λ= 9.9 × 10^ -8 m
b)
λ= 6.6 × 10^-34 × 3 × 10^8/0.65 × 1.6 × 10^-19
λ= 19.8 × 10^-26/1.04 ×10^-19
λ= 19.0 × 10^ -7 m