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Ratling [72]
3 years ago
13

Compute the permutations and combinations.A farmer buys 2 cows, 3 pigs, and 10 sheep from a seller who has 7 cows, 4 pigs, and 1

0 sheep. How many choices of animals does he have?845426
Mathematics
2 answers:
castortr0y [4]3 years ago
8 0

Answer:

84 :)

Step-by-step explanation:

aliya0001 [1]3 years ago
6 0

Farmer has 7 choice for cow out of which he choose only 2

4 choice for pig and he choose only 3 pigs

10 choice for sheep and he choose all 10 sheep

Number of ways of choosing cows = 7C2

Number of ways of choosing pigs = 4C3

number of ways of choosing sheep = 10C 10

all these three groups of different animals can make different groups when taken together

That is : 7C2 * 4C3 * 10C10 = 21 * 4 * 1 = 84 ways

Answer : 84

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