<span>If you deposit(P) $6,800 in a money-market account that pays an annual interest rate(r) of 5.7%. The interest is compounded quarterly(4). [ The money you have after 3 years(t) is: Using the compound interest formula A=P(1+r/n)^nt, where P=$6800, r=57%=.057,t=+3, n=4. A=$6,800(1+(0.057/4))^(3x4) =$6,800(1+0.01425)^12 =$6,800(1.01425)^12 =$6,800(1.18505961016) =$8,058.41. ]</span>
Answer:
Yeah it is correct
Step-by-step explanation:
you have already given your answer in the question!
Answer:
aₙ = aₙ₋₁ + aₙ₋₂
where:
a₁ = 6
a₂= 1.
Step-by-step explanation:
We have the sequence:
6, 1, 7, 8, 15, 23, ...
Is easy to see that this sequence works as follows:
You take 2 consecutive numbers, and the next number is the sum of these two.
Then we have:
6 + 1 = 7
1 + 7 = 8
7 + 8 = 15
8 + 15 = 23
Then the n-th term is equal to the sum of the (n - 1) term and the (n - 2) term.
This is written as:
aₙ = aₙ₋₁ + aₙ₋₂
Because in the recursive rule needs two previous terms, we need to specify the two first terms of the sequence.
Then we need to write also:
a₁ = 6
a₂= 1.
