All categories

3 years ago

S19for 11 + 19 + 27 + 35 +...

Mathematics

1 answer:

MrRissso [65]3 years ago

3 0

8 is the answer because it goes 11 and if you add 8 it becomes 19 add 8 it becomes 27 add 8 35 add 8 43

You might be interested in

Please help me asap! The drop down menu contains: Square Units Cubic Units Units

qwelly [4]

Answer:

Just units

Step-by-step explanation:

Looking for perimeter, not area and volume

6 0

2 years ago

Triangle DEF is an isosceles, so DEF = DFE.

Katarina [22]

Answer:

m∠CFD= $105\°$

Step-by-step explanation:

we know that

m∠CFD+m∠DFE= $180\°$ ------> by supplementary angles

we have

that

m∠DFE=m∠DEF= $75\°$

m∠CFD+ $75\°=180\°$

m∠CFD= $180\°-75\°=105\°$

8 0

3 years ago

Read 2 more answers

PLEASE SOMEONE DO THIS FOR ME: Determine the x - and y - intercepts of the following linear function: 4x + 8y =16

Kitty [74]

Answer:

x = 2 and y = 1

Step-by-step explanation:

4*2 = 8

8 * 1 =8

8+8=16

4(2) + 8(1) = 16

could pls have brainliest!!

3 0

2 years ago

Read 2 more answers

Demonstrate how you can use the slope formula to write the point-slope form of an equation of a line.

nevsk [136]

This is how I did it.

5 0

3 years ago

The time taken to deliver a pizza has a uniform probability distribution from 20 minutes to 60 minutes. What is the probability

Whitepunk [10]

Answer:

(1) The probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2a) The percentage of results more than 45 is 79.67%.

(2b) The percentage of results less than 85 is 91.77%.

(2c) The percentage of results are between 75 and 90 is 15.58%.

(2d) The percentage of results outside the healthy range 20 to 100 is 2.64%.

Step-by-step explanation:

(1)

Let Y = the time taken to deliver a pizza.

The random variable Y follows a Uniform distribution, U (20, 60).

The probability distribution function of a Uniform distribution is:

$f(x)=\left \{ {{\frac{1}{b-a};\ x\in [a, b] } \atop {0};\ otherwise} \right.$

Compute the probability that the time to deliver a pizza is at least 32 minutes as follows:

$P(Y\geq 32)=\int\limits^{60}_{32} {\frac{1}{b-a} } \, dx \\=\frac{1}{60-20} \int\limits^{60}_{32} {1 } \, dx\\=\frac{1}{40}\times[x]^{60}_{32}\\=\frac{1}{40}\times[60-32]\\=0.70$

Thus, the probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2)

Let X = results of a certain blood test.

It is provided that the random variable X follows a Normal distribution with parameters $\mu = 60$ and $s = 18$ .

The probabilities of a Normal distribution are computed by converting the raw scores to z-scores.

The z-scores follows a Standard normal distribution, N (0, 1).

(a)

Compute the probability that the results are more than 45 as follows:

$P(X>45)=P(\frac{X-\mu}{\sigma}> \frac{45-60}{18})=P(Z>-0.833)=P(Z$

The percentage of results more than 45 is: $0.7967\times100=79.67\%$

Thus, the percentage of results more than 45 is 79.67%.

(b)

Compute the probability that the results are less than 85 as follows:

$P(X$

The percentage of results less than 85 is: $0.9177\times100=91.77\%$

Thus, the percentage of results less than 85 is 91.77%.

(c)

Compute the probability that the results are between 75 and 90 as follows:

$P(75$

The percentage of results are between 75 and 90 is: $0.1558\times100=15.58\%$

Thus, the percentage of results are between 75 and 90 is 15.58%.

(d)

Compute the probability that the results are between 20 and 100 as follows:

$P(20$

Then the probability that the results outside the range 20 to 100 is: $1-0.9736=0.0264$ .

The percentage of results outside the range 20 to 100 is: $0.0264\times100=2.64\%$

Thus, the percentage of results outside the healthy range 20 to 100 is 2.64%.

4 0

3 years ago