Ask question

Ask question

All categories

4 years ago

7

A student found that the dimensions of a rectangle were 1.20 cm and 1.40 cm he was asked to report the area using the correct nu

mber of significant digits he reported the area as 1.7 cm² explain the error the student made

1 answer:

andrew-mc [135]4 years ago

6 0

Area of a rectangle is l x w
the student multiplied 1.2 x 1.4= 1.68 cm^2
the student should have NOT rounded the answer,
the problem said use significant digits

hope this helps

You might be interested in

Rewrite the expression with a rational exponent as a radical expression.

tatiyna

Answer:

First option is correct.

$\sqrt[10]{4}$

Step-by-step explanation:

Given:

The given expression is $(4^{\frac{2}{5}})^{\frac{1}{4}}$

We write the given expression with a rational exponent as a radical expression such as.

$=(4^{\frac{2}{5}})^{\frac{1}{4}}$

Simplify the above equation by multiplication of powers.

$=(4^{\frac{2}{5}\times \frac{1}{4}})$

$=(4^{\frac{1}{5}\times \frac{1}{2}})$

$=(4^{\frac{1}{5\times 2}})$

$=(4^{\frac{1}{10}})$

$=\sqrt[10]{4}$

Therefore, The answer is $=\sqrt[10]{4}$ .

4 0

4 years ago

I need this as soon as possible

GaryK [48]

Answer:

123.94

Step-by-step explanation:

8 0

3 years ago

A triangle with sides lengths of 17, 21, and 10. is this a right triangle?

USPshnik [31]

Use Pythagorean thrm
17^2+10^2=21^2
289+100=441
389≠441
This is not a right triangle

3 0

3 years ago

A point is chosen randomly on AD. What is the probability that the point is on BC?

Nadusha1986 [10]

I’m pretty sure it’s b but idk 100% sorry if it’s wrong

8 0

3 years ago

what is the perimeter of the triangle. i do not know how to start this problem. any help will be greatly appreciated :))

xz_007 [3.2K]

Given:

Point F,G,H are midpoints of the sides of the triangle CDE.

$FG=9,GH=7,CD=24$

To find:

The perimeter of the triangle CDE.

Solution:

According to the triangle mid-segment theorem, the length of the mid-segment of a triangle is always half of the base of the triangle.

FG is mid-segment and DE is base. So, by using triangle mid-segment theorem, we get

$\dfrac{1}{2}DE=FG$

$DE=2(FG)$

$DE=2(9)$

$DE=18$

GH is mid-segment and CE is base. So, by using triangle mid-segment theorem, we get

$\dfrac{1}{2}CE=GH$

$CE=2(GH)$

$CE=2(7)$

$CE=14$

Now, the perimeter of the triangle CDE is:

$Perimeter=CD+DE+CE$

$Perimeter=24+18+14$

$Perimeter=56$

Therefore, the perimeter of the triangle CDE is 56 units.

7 0

3 years ago