To find what the answer is for this problem, we need to find out whether each of them have infinite, no, or single solutions. We can do this individually.
Starting with the first one, we need to convert both of the equations into slope-intercept form. y = -2x + 5 is already in that form, now we just need to do it to 4x + 2y = 10.
2y = -4x + 10
y = -2x +5
Since both equations give the same line, the first one has infinite solutions.
Now onto the second one. Once again, the first step is to convert both of the equations into slope-intercept form.
x = 26 - 3y becomes
3y = -x + 26
y = -1/3x + 26/3
2x + 6y = 22 becomes
6y = -2x + 22
y = -1/3 x + 22/6
Since the slopes of these two lines are the same, that means that they are parallel, meaning that this one has no solutions.
Now the third one. We do the same steps.
5x + 4y = 6 becomes
4y = -5x + 6
y = -5/4x + 1.5
10x - 2y = 7 becomes
2y = 10x - 7
y = 5x - 3.5
Since these two equations are completely different, that means that this system has one solution.
Now the fourth one. We do the same steps again.
x + 2y = 3 becomes
2y = -x + 3
y = -0.5x + 1.5
4x + 8y = 15 becomes
8y = -4x + 15
y = -1/2x + 15/8
Once again, since these two lines have the same slopes, that means that they are parallel, meaning that this one has no solutions.
Now the fifth one.
3x + 4y = 17 becomes
4y = -3x + 17
y = -3/4x + 17/4
-6x = 10y - 39 becomes
10y = -6x + 39
y = -3/5x + 3.9
Since these equations are completely different, there is a single solution.
Last one!
x + 5y = 24 becomes
5y = -x + 24
y = -1/5x + 24/5
5x = 12 - y becomes
y = -5x +12
Since these equations are completely different, this system has a single solution.
<span>For this case we have the following equation:</span>
<span> (x + 2) 2 + y2 = 10</span>
<span> We must remember that the standard equation of the circle is given by:</span>
<span> (x - h) 2 + (y - k) 2 = r2</span>
<span> Where r is the radius.</span>
<span> Therefore, in the given equation the radius is:</span>
<span> r ^ 2 = 10</span>
<span> Clearing we have:</span>
<span> R = root (10)</span>
<span> Answer:</span>
<span> The length of the radius of the circle is:</span>
<span><span> √ (10)</span></span>
LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)
<h3>What is the limit of a function ?</h3>
The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.
It is given that
lim x->2 for f(x)

f(x) = 2x+1 x ≤2
f(x)= x² , x >2
When both the function tends to 2
Left Hand Limit
f(x) = 2 *2 +1
f(x) = 5
Right Hand Limit
f(x) = x² ,
f(x) = 4
LHL in not equal to RHL , Therefore the limit does not exists.
To know more about Limit of a Function
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Let's call the missing angles Q, R, and S. We know that Q = 2R and S = R - 8 and we also know that Q + R + S = 180. So that really just means that 180 = 4R - 8 Add 8 on both sides of the equal sign
188 = 4R So we divide on both sides of the equal sign by 4
47 = R And that means that Q = 2 * 47 So Q = 94 and S = 47 - 8 So S = 39
39 + 94 + 47 = 180
The missing angles are 39 degrees 94 degrees and 47 degrees.