Answer:
Step-by-step explanation:
in tri ADC and tri BDC
∠ADC =∠BDC = 90
DC is common
AD = BD (given)
triangle ADC ≅ tri BDC by SAS congruency
hence AC = BC by CPCT ( congruent parts of congruent triangles)
hence, BC = 13
Answer:
50x^4 +25x^3 +103x^2 +25x +49
(^3-^2+2)D=0
D^2+D^2+2D=0
2D^2+2D=0
a = 2; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·2·0
Δ = 4
D1=−b−Δ√2aD2=−b+Δ√2a
Δ−−√=4√=2
D1=−b−Δ√2a=−(2)−22∗2=−44=−1
D2=−b+Δ√2a=−(2)+22∗2=04=0
The answer will be 35 because it is a proportional side length
Answer:
BC = 40º
BMC = 40º
Step-by-step explanation: Since the measure the major and minor arcs add up to 360º, just subtract 320 from 360 to find BC which is 40º. <BMC is also 40º because the measure of the arc is equal to its corresponding angle.
