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Marta_Voda [28]
3 years ago
14

Solve the system of linear equations below. 2x + y = 5 x + y = 4

Mathematics
2 answers:
bekas [8.4K]3 years ago
7 0
X=4-Y
8-2Y+Y=5
8-Y=5
Y=3
X=4-3
=1

X=1, Y=3
Julli [10]3 years ago
6 0
Lets see what we're working on, in this problem.

▶Your solutions
⚫Solution 1: 2(x) + y = 5
⚫Solution 2: x + y = 4

▶Your graphic organizer
⚫y + 2(x) = 5
⚫ y + x = 4

▶In the solution #2, the value of 'x' becomes a negative number; we had to look for the y-intercept.
⚫ y = -x + 4
~From the looks of it, we didnt find the y-intercept in the second solution

▶ Lets look for the x-intercept in the solution #1
⚫2(x) + (-x +4) = 5
~From the looks of it , we have found the x-intercept in the first solution
⚫x-intercept: 1

▶Since we didnt find the y-intercept in the solution, we have to look for it in the first solution.
⚫x-intercept: 1
y = -1 + 4 = 3
~We have found the y-intercept in the first solution
⚫ y-intercept: 3

Your answer: {x-intercept: 1; y-intercept: 3


Good Luck!









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Step-by-step explanation:

We have a total of 10 members, and we want to find how many groups of 2 members we can have, where the order of each member in the group of 2 is important, so we have a permutation problem.

To solve this problem, we need to calculate a permutation of 10 choose 2.

The formula for a permutation of n choose p is:

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So we have:

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