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Studentka2010 [4]
4 years ago
15

The elivation of city A is 60 feet above sea level; the elevation of city C is 12 feet above sea level. The elevation of city D

is 1/2 of the elevation of city c. How do you represent the elevation, in feet, of city d?
Mathematics
1 answer:
serg [7]4 years ago
6 0
Go to openstudy.com for real help with homework.
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Please help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!
docker41 [41]

Using the formulas :

A=2AB+(a+b+c)h

AB=√(s(s﹣a)(s﹣b)(s﹣c) )

s = (a+b+c)  / 2

Solving for A:

A=ah+bh+ch+1 /2 √(﹣a∧4+2(ab)∧2+2(ac)∧2﹣b∧4+2(bc)∧2﹣c∧4)

=2·1.7+3·1.7+2·1.7+1 /2· √(﹣2∧4+2·(2·3)∧2+2·(2·2)∧2﹣3∧4+2·(3·2)∧2﹣24)

≈15.86863

5 0
3 years ago
Parallelogram RECT is a rectangle. If EC = x + y , RT = 2x - y, RE = 2x + y, and TC = 3x - 3 , what are the values of the variab
Lady_Fox [76]
<h2>The values of the variable are 3 and 6.</h2>

Step-by-step explanation:

In parallelogram RECT is a rectangle,

EC = x + y , RT = 2x - y, RE = 2x + y and TC = 3x - 3

To find, the values of the variable = ?

∵ The opposite sides are equal.

∴ RE = TC and RT = EC

2x + y = 3x - 3

⇒ x - y = 3                   .......... (1)

Also,

2x - y = x + y

⇒ x - 2y = 0               .......... (2)      

Subtracting (1) from (2), we get

∴ x - y - (x - 2y ) = 3 - 0

⇒ x - y - x + 2y = 3

⇒ y = 3

Put y = 3 in equation (1), we get

x - 3 = 3  

⇒ x = 3 + 3 = 6

∴ x = 6 and y = 3

Thus, the values of the variable are 3 and 6.

8 0
4 years ago
I need help please !!!!
agasfer [191]
8^{b-1}=2^{4b+4}\\\\\left(2^3\right)^{b-1}=2^{4b+4}\\\\2^{3(b-1)}=2^{4b+4}\iff3(b-1)=4b+4\\\\3b-3=4b+4\ \ \ |+3\\\\3b=4b+7\ \ \ |-4b\\\\-b=7\to \boxed{b=-7}

\text{check:}\\\\L_s=8^{-7-1}=8^{-8}=(2^3)^{-8}=2^{3\cdot(-8)}=2^{-24}\\\\R_s=2^{4\cdot(-7)+4}=2^{-28+4}=2^{-24}\\\\L_s=R_s\ \ \ \text{CORRECT :)}

\text{Used:}\\(a^n)^m=a^{n\cdot m}

4 0
4 years ago
A truck and a car leave a service station at the same time and travel in the same direction. The truck travels at 52 mph and the
Serggg [28]

Answer:

After 1.5 hours

Step-by-step explanation:

The truck and the car are moving in the same direction after they left the service station at the same time. The truck travels at 52 miles per hour and the car at 44 miles per hour.

Let us assume that after h hours their distance from each other will be 12 miles.

So, 52h - 44h = 12

⇒ 8h = 12

⇒ h = 1.5 hours.

Therefore, after 1.5 hours their distance from each other will be more than 12 miles and their radio contact will be lost after that. (Answer)

7 0
4 years ago
13 Points!! Need help ASAP
oksano4ka [1.4K]

Answer:

The answer is D

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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