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bekas [8.4K]
4 years ago
13

Does anyone know how to evaluate this problem? im stuck

Mathematics
1 answer:
shusha [124]4 years ago
5 0
If you are just supposed to evaluate the a) f(0) and b) f(4) then you would just plug it in the equation.
f(0)=0^2 - 8*0 + 16
f(0)=0 - 0 + 16
f(0)=16
f(4)=4^2 - 8*4 +16
f(4)=16 - 32 + 16
f(4)=0
Feel free to comment any questions and if there is any additional context to the question please say so I can help with that.
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x,z,y = 20,15,-33

i think thats it im sorry
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30mL:45mL simplify the ratio
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30ml:45ml\\\\\dfrac{30}{45}=\dfrac{30:5}{45:5}=\dfrac{6}{9}=\dfrac{6:3}{9:3}=\dfrac{2}{3}\\\\\boxed{30ml:45ml=2ml:3ml}
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Urrrrrrrrrrrrrrerrrrrr
Alenkasestr [34]

Answer:

answer = -12

Step-by-step explanation:

substitute y as -3 and z as 4

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Help me I need help I need help
Licemer1 [7]

Answer:

\Huge\boxed{131.88}

Step-by-step explanation:

Hello There!

First thing we want to do is find the formula for circumference of a circle

C = 2(3.14)r

where r = radius

we are given the diameter so we have to convert that into radius to do so we just divide by 2

42/2=21 so the radius equals 21 inches

now we just plug in 21 for r in the formula

C = 2(3.14)21\\2*3.14=6.28\\6.28*21=131.88\\C=131.88

So we can conclude that the circumference of the circle is 131.88 inches

3 0
3 years ago
6. An ostrich cannot fly, but it is able to run fast. Suppose an ostrich runs east for 7.95 s and then runs 161 m south, so that
Liula [17]

Answer:

159 m

Step-by-step explanation:

From the information given:

It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.

Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.

Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.

We are to find, the magnitude of the ostrich's eastward component.

i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.

Using the Pythagoras rule:

ES² = OE² + OS²

226² = OE² + 161²

226² -  161² = OE²

OE²  =  226² -  161²

OE²  = 51076 - 25921

OE²  =  51076 - 25921

OE²  =  25155

OE = \sqrt{25155}

OE =  158.60 m

OE ≅ 159 m

Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.

4 0
3 years ago
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