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frez [133]
3 years ago
6

If a 45 45 90 triangle has the hypothenuse of 10 what would the legs x and y be

Mathematics
1 answer:
melamori03 [73]3 years ago
3 0

Answer:

Step-by-step explanation:

When working with 45-45-90 triangles the hypotenuse is the same as the other legs multiplied by root 2. Therefore if you need to find the legs and already have the hypotenuse, divide the hypotenuse by root 2.

10/ sqrt(2) = 7.1 is the rounded answer.

to double check your work just multiply 7.1 by the square root of 2 and you'll get <em>close</em> to 10. (because the answer is rounded and not exact.)

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A circle with circumference 20 has an arc with 72 degree central angle what is length of the arc
Debora [2.8K]

Answer:

<h2>4</h2>

Step-by-step explanation:

<em>Look at the picture.</em>

<em />

<em>At the beginning we have to calculate what part of the angle 360° is the given angle 75°.</em>

<em />\dfrac{75}{360}=75:360=0.2<em />

<em>The same part of the circumference of the circle is the arc defined by this central angle.</em>

The circumference <em>C = 20</em>.

Therefore

x=0.2\cdot20=4

4 0
2 years ago
Andrea's car get 25 miles per gallon of gas. The cabin is 190 miles away. How many gallons of gas will she need to get there?
Romashka [77]
190 miles / 25 miles
=7.6 gallons
3 0
3 years ago
Read 2 more answers
PLEASE 10 PTS!!
ira [324]
Its c because first 14 he got -42 the four remaining he got 8=-34
6 0
3 years ago
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A small regional carrier accepted 16 reservations for a particular flight with 12 seats. 8 reservations went to regular customer
wolverine [178]

Answer:

a) 32.04% probability that overbooking occurs.

b) 40.79% probability that the flight has empty seats.

Step-by-step explanation:

For each booked passenger, there are only two possible outcomes. Either they arrive for the flight, or they do not arrive. The probability of a passenger arriving is independent of other passengers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Our variable of interest are the 8 reservations that went for the passengers with a 48% probability of arriving.

This means that n = 8, p = 0.48

A) Find the probability that overbooking occurs.

12 seats, 8 of which are already occupied. So overbooking occurs if more than 4 of the reservated arrive.

P(X > 4) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{8,5}.(0.48)^{5}.(0.52)^{3} = 0.2006

P(X = 6) = C_{8,6}.(0.48)^{6}.(0.52)^{2} = 0.0926

P(X = 7) = C_{8,7}.(0.48)^{7}.(0.52)^{7} = 0.0244

P(X = 8) = C_{8,5}.(0.48)^{8}.(0.52)^{0} = 0.0028

P(X > 4) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) = 0.2006 + 0.0926 + 0.0244 + 0.0028 = 0.3204

32.04% probability that overbooking occurs.

B) Find the probability that the flight has empty seats.

Less than 4 of the booked passengers arrive.

To make it easier, i will use

P(X < 4) = 1 - (P(X = 4) + P(X > 4))

From a), P(X > 4) = 0.3204

P(X = 4) = C_{8,4}.(0.48)^{4}.(0.52)^{4} = 0.2717

P(X < 4) = 1 - (P(X = 4) + P(X > 4)) = 1 - (0.2717 + 0.3204) = 1 - 0.5921 = 0.4079

40.79% probability that the flight has empty seats.

4 0
2 years ago
Which statement best applies to the function y = x squared?
tekilochka [14]

Answer:

b.  The range only includes numbers greater than or equal to 0.

Step-by-step explanation:

Any square of a number will never lead to a negative number

The range of an equation is it's numerical possibilities for y

Since a square of a negative number never leads to a negative y

The answer is therefore, the range can only be zero and above

(otherwise the roots would be imaginary)

3 0
2 years ago
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