ANSWER:
- x – 3y = 2 ...(1)
- 2x – 6y = 6 ...(2)
On solving eq(1), we get
Plug the value of x in eq(2)
- 2x – 6(x - 2/3) = 6
- 2x – 2(x – 2) = 6
- 2x – 2x + 4 = 6
- 0 = 6 – 4
- 0 ≠ 2
So, given system of equations is not correct.
Answer:
A: The triangle in question is not a right triangle.
Step-by-step explanation:
If the triangle is a right triangle, then the Pythagorean theorem would hold
a^2 + b^2 = c^2
3^2 + 4^2 = 6^2
9+16 = 36
25 = 36
This is not true so this is not a right triangle
I don't understand please be specific
Answer:
Step-by-step explanation:
- 4x² - 36x + 81 = 0
- (2x)² - 2*2x*9 + 9² = 0 Identity a² - 2ab + b² = (a - b)²
- (2x - 9)² = 0
- 2x - 9 = 0
- 2x = 9
- x = 4.5
