Given options : Two intersecting circles are drawn with a radius in each marked. the image will be linked.
Given options : An equilateral triangle inscribed in a circle
A square inscribed in a circle
A regular pentagon inscribed in a circle
A regular hexagon inscribed in a circle.
<u>Note. When we join an intersection point of two circles and centers of the circles it would form an equilateral triangle that would be inscribe inside a common portion of both circles..</u>
Therefore, an equilateral triangle inscribed in a circle would be correct option.
She is completing an equilateral triangle inscribed in a circle.
Answer:
it's J
Step-by-step explanation
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Well the LCM (lowest common multiples) for 8 and 32 would be 4. So plug 4 into "b" -8×4-32. -8×4=32. -32-32. Since you can't subtract 32 and 32 you add! Which gives you -64.
Hope this helps (:
Answer:
Solution given:
length[a]=3cm
base(b)=7cm
hypotenuse [c]=?
we have
by using Pythagoras law
a²+b²=c²
3²+7²=c²
c=√58=7.61m
<u>the length of the hypotenuse is 7.61</u><u> </u><u>o</u><u>r</u><u> </u><u>7</u><u>.</u><u>6</u><u> </u><u>o</u><u>r</u><u>8</u><u>m.</u>
Divide 259 by 7 (259/7)= 37 beads per necklace. If you wanted to check just multiply 7 and 37 (37x7)=259
