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Schach [20]
4 years ago
12

The standard deviation is used in conjunction with the _________ (range/variance/median/mean/mode) to numerically describe distr

ibutions that are bell shaped. The _________(range/variance/standard deviation/mean) mean standard deviation range variance measures the center of the​ distribution, while the standard deviation measures the _________(spread/range/center of the distribution).
Mathematics
1 answer:
NNADVOKAT [17]4 years ago
7 0

Answer:

The standard deviation is used in conjunction with the mean to numerically describe distributions that are bell shaped. The mean measures the center of the​ distribution, while the standard deviation measures the spread of the distribution.

Step-by-step explanation:

How we solve bell shaped distributions?

Problems of normally distributed(bell-shaped) samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

So

Mean = center

Standard deviation = spread.

So the correct answer is:

The standard deviation is used in conjunction with the mean to numerically describe distributions that are bell shaped. The mean measures the center of the​ distribution, while the standard deviation measures the spread of the distribution.

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Answer:

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A path 5m wide is to be built along the border and inside a square garden of side 90m. Find the cost of cementing the path at th
gizmo_the_mogwai [7]

Answer:

Total cost of cementing the path = Rs. 17,000.

Step-by-step explanation:

Let the square garden be ABCD

Let the region inside the garden (ABCD) be WXYZ.

<u>Given the following data;</u>

Length of sides of ABCD = 90m

Width of path = 5m

Cost = Rs. 10 per m²

Area of ABCD = 90 * 90

Area of ABCD = 8100m²

<em>To find the area of WXYZ;</em>

WX = WZ = 90 - (5 + 5)

WX = WZ = 90 - 10

WX = WZ = 80m

Area of WXYZ = WX * WZ

Substituting into the equation, we have;

Area of WXYZ = 80 * 80

Area of WXYZ = 6400 m²

Area of path = Area of ABCD - Area of WXYZ

Area of path = 8100 - 6400

Area of path = 1700 m²

Total cost of cementing the path = Area of path * cost

Total cost of cementing the path = 1700 * 10

<em>Total cost of cementing the path = Rs. 17,000</em>

6 0
3 years ago
Given h(x)=2x+5h(x)=2x+5, find h(-6)h
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7

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Answer:

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Given that Mrs Bain earns $30,483 per year.

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Hence earning per month = \frac{30483}{12}

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Answer:

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Step-by-step explanation:

379 * 8 = 3032

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4 years ago
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