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azamat
3 years ago
13

Find the product of 0.032 and -1.9

Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0

Answer:

i think it's -0.0608

Step-by-step explanation:

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What is the answer for15/8=80/x
-Dominant- [34]
\frac{15}{8} = \frac{80}{x}
At this point in time, you can use a technique called cross-mutiplication, where you say that 15*80=8x, and 1200=8x at this point in time, you can devide each side by 8 and solve
5 0
3 years ago
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The area of Terry's room at the old house was 96 ft.2. The area of Terry's room at the new house is 108 ft.2
Finger [1]

Answer:

12.5%

Step-by-step explanation:

First we need to calculate the change in the area of Terry's room this is

108 ft2 - 96 ft2 = 12 ft2

Then we use a direct proportion in order to find the percentage

96 ft2 ----- 100%

12 ft2 ----- p?

Solvin for p we have that

p=\frac{12\times 100}{96}

p=12.5

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3 years ago
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Select the correct answer
soldi70 [24.7K]

Answer:

The Expression h(-7) represents the output of h corresponding to the input of -7

Step-by-step explanation:

7 0
3 years ago
Is 80 a multipul of 10 Asap help or i'll fail
astraxan [27]

Answer:

yes

Step-by-step explanation:

10 20 30 40 50 60 70 80 90 100 etc

4 0
2 years ago
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it takes someone 15 minutes to prepare 3 1/4 cups of juice how many hours would it take to prepare 32 1/2 cups of juice​
wariber [46]

\bf \begin{array}{ccll} minutes&\stackrel{juice}{cups}\\ \cline{1-2} 15&3\frac{1}{4}\\\\ x&32\frac{1}{2} \end{array}\implies \cfrac{15}{x}=\cfrac{3\frac{1}{4}}{32\frac{1}{2}}\implies \cfrac{15}{x}=\cfrac{\frac{3\cdot 4+1}{4}}{\frac{32\cdot 2+1}{2}}\implies \cfrac{15}{x}=\cfrac{\frac{13}{4}}{\frac{65}{2}}

\bf \cfrac{15}{x}=\cfrac{~~\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\underset{2}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\underset{5}{~~\begin{matrix} 65 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{15}{x}=\cfrac{1}{10}\implies 150=x\leftarrow \begin{array}{llll} \textit{150 minutes or}\\\\ \textit{2 hours and a half} \end{array}

4 0
2 years ago
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