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Alika [10]
3 years ago
9

The data from the previous table is

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
7 0

Zero-max-zero-min-zero

Just did it on edge2020

anzhelika [568]3 years ago
6 0

Answer:

Please add more info.

Step-by-step explanation:

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In 2001 , chipper had 102 runs batted in. In 2008, Chipper had only 75 runs batted in. Calculate the percent change in runs batt
DerKrebs [107]

Answer:

The percent change in runs batted in from 2001 to 2008 is 26.47%

Step-by-step explanation:

The number of runs chipper batted in the year 2001  = 102 runs

The number of runs chipper batted in the year 2008  = 75 runs

Here, so the Change in the runs batted

= Runs Batted in year 2001 - Runs batted in the year 2008

= 102 runs - 75 runs  =  27 runs

Now, The percentage change in the run = = \frac{\textrm{Change in the batted run from 2001 to 2008}}{\textrm{Total number of batted runs in 2001}}  \times 100

= \frac{27}{102}  \times 100 = 26.47

or, The percentage change = 26.47%

Hence, the percent change in runs batted in from 2001 to 2008 is 26.47%

5 0
3 years ago
Solve in(5x+7)=8 round to the nearest thousandth
Ivan

Answer:

x=\frac{1}{5}

x=0.2

Step-by-step explanation:

(5x+7)=8

5x+7=8

Subtract 7 from both sides.

5x+7-7=8-7

Simplify.

5x=1

Divide both sides by 5.

\frac{5x}{5} =\frac{1}{5}

Simplify.

x=\frac{1}{5}

Decimal form:

0.2

7 0
3 years ago
Read 2 more answers
Please answer this correctly without making mistakes
faltersainse [42]

Answer:

so to get a third you divide it by 3

first convert it to fraction

so it is 26/3

so do 26/3 divided by 3

so we do keep switch flip

26/3*1/3

so answer is 26/9 or 2 8/9

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help me ASAP I have a 67% I math the girlie needs help
tia_tia [17]

Answer:

x=28

Step-by-step explanation:

4(x-5)=92

4x-20=92

add 20 to both sides

4x=112

divide 4 on both sides

x=28

5 0
3 years ago
Read 2 more answers
Use the divergence theorem to find the outward flux of the vector field F(xyz)= 4x^2 i + 4y^2 j + 3z^2 k across the boundary of
Pavel [41]

\vec F(x,y,z)=4x^2\,\vec\imath+4y^2\,\vec\jmath+3z^2\,\vec k\implies\nabla\cdot\vec F=8x+8y+6z

Let S be the surface of the rectangular prism bounded by the planes x=0, x=a, y=0, y=b, z=0, and z=c. By the divergence theorem, the integral of \vec F over S is given by the integral of \nabla\cdot\vec F over the interior of S (call it R):

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV

=\displaystyle\int_0^c\int_0^b\int_0^a(8x+8y+6z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=\boxed{abc(4a+4b+3c)}

5 0
3 years ago
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