Answer:
The answer is explained below
Step-by-step explanation:
The question is not complete we need point P and point Q.
let us assume P is at (3,1) and Q is at (-2,4)
To find the coordinate of the point that divides a line segment PQ with point P at
and point Q at
in the proportion a:b, we use the formula:

line segment PQ is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

X= 23 degrees
To find this you first add up 124 and 33 which equals 157. Then you would subtract 157 from 180 because all triangles equal 180.
A. 32500
b. 60,400
c. 2.4 x 10 ^ -6
d. 1.47 x 10 ^3
Given:
Angled formed by ray BA and ray BC is 90 degrees.
To find:
The equation of line that bisects the angle formed by ray BA and ray BC.
Solution:
If a line bisects the angle formed by ray BA and ray BC, then it must be passes through point B and makes angles of 45 degrees with ray BA and ray BC.
It is possible if the line passes though point B(-1,3) and other point (-2,4).
Equation of line is




Add 3 on both sides.


Therefore, the required equation of line is
.
We know that <span>the given side lengths are x and the height is x.
Therefore, the area of the base = </span>


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