Write the quotient with the decimal point placed correctly 0.42 divided by 0.35= 12

Help, please!!! Simplify. (4/9)^2=

alina1380 [7]

Answer:

Exact form: $\frac{16}{81}$

Decimal form: 0.1975308

8 0

2 years ago

A tank pumps out liquid at a rate of 12 gallons every 20 days. What is the unit rate in gallons per week?

pashok25 [27]

Answer:

4.2

Step-by-step explanation:

simplify 12 and 20 to 6 and 10 then divide 6 by 10 and multiply by 7 to get the answer.

8 0

3 years ago

if angle 1 and angle 2 form a linear pair. if m<1=5x+9 and m<2=3x+11, find the measure of both angles

Ulleksa [173]

Answer: $m\angle 1=109\°\\m\angle 2=71\°$

Step-by-step explanation:

It is important to remember the definition of "Linear pair angles".

By definitiion "Linear pair angles" are two angles which are adjacents and supplementary.

Based on this, we know that the angles $\angle1$ and $\angle2$ are supplementary, which means that they add up to 180 degrees.

So, knowing that:

$m\angle 1=5x+9\\m\angle 2=3x+11$

We can write the following expression and solve for "x":

$(5x+9)+(3x+11)=180\\\\8x=180-20\\\\x=\frac{160}{8}\\\\x=20$

Therefore, substituting, we get that the measures of the angles $\angle1$ and $\angle2$ are:

$m\angle 1=5(20)+9=109\°\\\\\\m\angle 2=3(20)+11=71\°$

8 0

3 years ago

PLEASE HELP

almond37 [142]

Answer:

x + 6y = -3

Step-by-step explanation:

Explained in the paper.

8 0

3 years ago

Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

Algebra I

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle L = \sqrt{4kt - p}$

Step 2: Solve for k
We can use equality properties to help us rewrite the equation to get k as our subject:

Let's first square both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, add p to both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, divide 4t by both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$

We can rewrite the new equation by swapping sides to obtain our final expression:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}$

∴ we have changed the subject of the formula.

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Learn more about Algebra I: brainly.com/question/27698547

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Topic: Algebra I

6 0

2 years ago