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sesenic [268]
3 years ago
13

3) When the temperature of a blackbody increases from 900 K to 2300 K, by what factor does the total power of the electromagneti

c radiation per-unit- area increase?
Geography
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

The electromagnetic radiation per-unit- area increase by 42.65 times.

Explanation:

The radiation per-unit- area (P) is directly proportional to the fourth power of the temperature. Thus,

P ∝ T⁴

For, when the temperature is raised from T₀ to T₁ , the radiation per-unit- area is related to as:

\frac {P_1}{P_0}=\frac {T_1^4}{T_0^4}

T₀ =  900 K

T₁ = 2300 K

\frac {P_1}{P_0}=\frac {2300^4}{900^4}

So,

<u>P₁ = 42.65 P₀</u>

<u>The electromagnetic radiation per-unit- area increase by 42.65 times.</u>

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