Answer:
8
Step-by-step explanation:
The midpoint of AC is ...
B = (A +C)/2 = (-10 +14)/2 = 2
The midpoint of BC is ...
D = (B +C)/2 = (2 +14)/2 = 8
The midpoint of BC is 8.
2 8 −10−15÷3=2, start superscript, 8, end superscript, minus, 10, minus, 15, divided by, 3, equals
Sergio039 [100]
Answer:
241
Step-by-step explanation:
Given the equation to evaluate :
2^8 −10−15÷3
2^8 = 256
256 - 10 - 15 ÷ 3
From BODMAS principle, we evaluate the divison before subtraction :
-15 ÷ 3 = - 5
256 - 10 -5
256 - 15
= 241
Solve for x: x^2+4x-5=16x
first take 16x from both sides of the equation
x²-12x-5=0
now we have a quadratic. we can solve it by using the quadratic formula
x=-b plus or minus the square root of b²-4ac all divided by 2a
where a=1, b=-12 and c=-5
plug these numbers into the formula
x=12 plus or minus the square root of 144-4x1x-5 all divided by 2
<span>x=12 plus or minus the square root of 164 all divided by 2
or in decimal form </span>x = {12.403124237, -0.403124237}
