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lesya692 [45]
2 years ago
10

Alejandra plans to sew fringe on a scarf. The scarf is shaped rectangle. The length of the scarf is 48 inches. The width is one

half the length. How many fringe does Alejandra need?
Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
5 0
Ok so you will be finding the perimeter of this rectangle. The formula is P(perimeter)=2L(length) + 2W(width)

so the length is 48 and the width is 1/2 of 48, and we all know that 1/2 of 48 = 24 right? so in the formula is says 2L so we will take 48 and multiply it by 2 and get 96. The same way with the width. 24 times 2 = 48 so then we add them together and get 144. Therefore the perimeter and the length of fringe that she will use (or how ever you say it) will be 144 inches.

Hope this helps!;)
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How many zeroes do we write when we write all the integers 1 to 243 in base 3?
Monica [59]

Answer:

289 numbers

Step-by-step explanation:

Above you will find the list of integers from 1 to 243 in base 3:

(1, 2, 10, 11, 12, 20, 21, 22, 100, 101, 102, 110, 111, 112, 120, 121, 122, 200, 201, 202, 210, 211, 212, 220, 221, 222, 1000, 1001, 1002, 1010, 1011, 1012, 1020, 1021, 1022, 1100, 1101, 1102, 1110, 1111, 1112, 1120, 1121, 1122, 1200, 1201, 1202, 1210, 1211, 1212, 1220, 1221, 1222, 2000, 2001, 2002, 2010, 2011, 2012, 2020, 2021, 2022, 2100, 2101, 2102, 2110, 2111, 2112, 2120, 2121, 2122, 2200, 2201, 2202, 2210, 2211, 2212, 2220, 2221, 2222, 10000, 10001, 10002, 10010, 10011, 10012, 10020, 10021, 10022, 10100, 10101, 10102, 10110, 10111, 10112, 10120, 10121, 10122, 10200, 10201, 10202, 10210, 10211, 10212, 10220, 10221, 10222, 11000, 11001, 11002, 11010, 11011, 11012, 11020, 11021, 11022, 11100, 11101, 11102, 11110, 11111, 11112, 11120, 11121, 11122, 11200, 11201, 11202, 11210, 11211, 11212, 11220, 11221, 11222, 12000, 12001, 12002, 12010, 12011, 12012, 12020, 12021, 12022, 12100, 12101, 12102, 12110, 12111, 12112, 12120, 12121, 12122, 12200, 12201, 12202, 12210, 12211, 12212, 12220, 12221, 12222, 20000, 20001, 20002, 20010, 20011, 20012, 20020, 20021, 20022, 20100, 20101, 20102, 20110, 20111, 20112, 20120, 20121, 20122, 20200, 20201, 20202, 20210, 20211, 20212, 20220, 20221, 20222, 21000, 21001, 21002, 21010, 21011, 21012, 21020, 21021, 21022, 21100, 21101, 21102, 21110, 21111, 21112, 21120, 21121, 21122, 21200, 21201, 21202, 21210, 21211, 21212, 21220, 21221, 21222, 22000, 22001, 22002, 22010, 22011, 22012, 22020, 22021, 22022, 22100, 22101, 22102, 22110, 22111, 22112, 22120, 22121, 22122, 22200, 22201, 22202, 22210, 22211, 22212, 22220, 22221, 22222, 100000)

If you count them, you will find that there are 289 numbers in total!

8 0
3 years ago
1 7/11 X 2 5/6 find the product
lana66690 [7]
1 7/11  = 18/11

2 5/6  = 17/6


Product = 18/11 * 17/6

 =  306 / 66  = 51/11  = 4 7/11  Answer
3 0
3 years ago
Read 2 more answers
The set S contains some real numbers, according to the following three rules. (i) 1 1 is in S. (ii) If a b is in S, where a b is
pogonyaev

Answer:

The solution is given in the pictures below

Step-by-step explanation:

4 0
2 years ago
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Virty [35]

Answer:

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Step-by-step explanation: horizon shows where the dotted line crosses the y axis

7 0
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Nitella [24]

Answer:

1st and 2nd quadrants

Step-by-step explanation:

You have sine is positive since it is 4/5.

Sine is the y-coordinate.

On the coordinate plane y is positive in the 1st and 2nd quadrants.

8 0
3 years ago
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