I need to solve for X

A typical credit card company charges 18% annual interest,

AnnZ [28]

Answer:

$1,519

Step-by-step explanation:

Given that :

Balance = principal = $520

Time (t) = 6 years

Annual. Interest rate (r) = 18% = 0.18

Using the compound interest formula:

A = P(1 + r/n)^nt

n = number of times interest is applied per period ; A = final amount

Since interest is compounded monthly, n = 12

A = 520(1 + 0.18/12)^(12 * 6)

A = 520(1 + 0.015)^72

A = 520(1.015)^72

A = 520(2.9211579)

A = 1519.0021

Hence, final amount = $1519

3 0

3 years ago

Last week, a GameStop store sold some $43 games and some $30 games for a total of

Vesnalui [34]

Answer: The total number of games sold by the GameStop is 14. That is 5 games of $43 and 9 games of $30.

Step-by-step explanation:

Considering some games of $43 were sold and others for $30 were also sold in arriving at the total of $485 sold.

If 5 games of $43 were sold it gives $215.

To get the difference, you subtract the amount sold for $43 from the total.

$485 - $215 = $270

To arrive at how many $30 games were sold;

$270 ÷ $30 per game = 9 games

Therefore, 5 games of $43 combined with 9 games of $30 gives a total of 14 games.

6 0

3 years ago

A distribution of scores for a test of life stressors has a mean of µ = 125 and standard deviation of σ = 15. The researcher cal

laila [671]

Answer:

The mean and standard deviation for the z-scores in this distribution are 0 and 1 respectively.

Step-by-step explanation:

Let the random variable X follow a Normal distribution with mean μ and standard deviation σ.

The z-scores are standardized form of the raw scores X. It is computed by subtracting the mean (μ) from the raw score x and dividing the result by the standard deviation (σ).

$z=\frac{x-\mu}{\sigma}$

These z-scores also follow a normal distribution.

The mean is:

$E(z)=E[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma}\times [E(x)-\mu] =\frac{1}{\sigma}\times [\mu-\mu]=0$

The standard deviation is:

$Var(z)=Var[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma^{2}}\times [Var(x)-Var(\mu)] =\frac{\sigma^{2}-0}{\sigma^{2}}=1\\SD(z)=\sqrt{Var(z)}=1$

Thus, the mean and standard deviation for the z-scores in this distribution are 0 and 1 respectively.

8 0

3 years ago

A standard deck of 52 cards contains 13 cards with hearts, 13 with diamonds, 13 with clubs, and 13 with spades. How

PIT_PIT [208]

Answer:

133,784,560

Step-by-step explanation:

using the combinations formula: n!/(n-r!)r!, the equation would be 52!/52-7! x 7! which is simplified to 52!/45!7! which is equal to 133,784,560

7 0

3 years ago

The width of a rectangle is 9 in. shorter than its length. The area of the rectangle is 252 in². What is the length of the recta

erastovalidia [21]

Answer:

the length of the rectangle is, 21 in.

Step-by-step explanation:

Area of the rectangle(A) is given by:

$A=lw$ .....[1]

where,

l is the length of the rectangle

w is the width of the rectangle.

As per the statement:

The width of a rectangle is 9 in. shorter than its length.

⇒ $w = l-9$

It is also given that:

The area of the rectangle is 252 in².

⇒A = 252 in².

Substitute in [1] we have;

$252 = l(l-9)$

⇒ $252 = l^2-9l$

⇒ $l^2-9l -252 = 0$

Factorize this equation:

Split the middle term;

⇒ $l^2-21l+12l-252=0$

⇒ $l(l-21)+12(l-21)=0$

⇒ $(l-21)(l+12)=0$

By zero product property we have;

$l-21 =0$ and $l+12 =0$

⇒ $l = 21$ and $l = -12$

Since, length cannot be in negative

⇒ $l = 21 in.$

Therefore, the length of the rectangle is, 21 inches.

4 0

3 years ago