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Margarita [4]
2 years ago
11

Show me how to solve

Mathematics
1 answer:
Sedbober [7]2 years ago
3 0
Draw the shape by drawing dots at the co-ordinates. 
Connect them in order, so if it's KLMN, connect K to L then to M then N.
Then, pick one of the points, I'd choose K, then move that dot 3 to the right, then move it 4 up. Do the same for all of the letters.
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The sum of 3 consecutive odd #s is 51 what are the 3#s?
kari74 [83]

Answer: 15, 17, 19

Step-by-step explanation:

8 0
3 years ago
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What is the domain of the set of ordered pairs {(−5,−4),(−4,4),(2,3),(4,5)}?
kvv77 [185]

Answer:

{-5,-4,2,4}

Step-by-step explanation:

the domain is which x-values are included so use each of the x-values for each pair. Make sure if there are reapeats that you only write them once.

3 0
2 years ago
Simplify i12<br><br> A.-1<br> B.-i <br> C.i <br> D.1
yuradex [85]

Answer:

D 1

Step-by-step explanation:

i^12

We know i^4 = 1

Rewriting

i^4^3

1^3

1

7 0
2 years ago
What is the soloution to the equation 3x+4=7x-4​
VMariaS [17]
Answer: 2=x
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-3x -3x
4=4x-4
+4 +4
8=4x
(divide each side by 4)
2=x
5 0
3 years ago
Read 2 more answers
An inscribed triangle with the hypotenuse being the diameter of the circle has angle A be 42 degrees. Angle C is 90 degrees. The
eduard

Answer:

The Radius of circle is 7.15 cm  

Step-by-step explanation:

Given as :

A Triangle is inscribed into circle

The center of circle is O

The Diameter of circle = AK = d

The hypotenuse of triangle being the diameter of circle

The Area of triangle = 50 cm²

Let The radius of circle = r cm

The Triangle is right angle at c

So , ∠ACK = 90°

∠CAK = 42°

∠AKC = 180° - (90° + 42°)

So, ∠AKC = 48°

Now, ∵ Area of triangle ACK = 50 cm²

So, \dfrac{1}{2} × AC × CK = 50

Or, AC × CK = 50 × 2

i.e , AC × CK = 100        ..........1

From figure

Sin 48° =  \dfrac{AC}{AK}

Or, 0.74 =  \dfrac{AC}{d}

∴ AC = 0.74 d             ..........2

<u>Similarly</u>

Sin 42° =  \dfrac{CK}{AK}

Or, 0.66 =  \dfrac{CK}{d}

∴ CK = 0.66 d               .............3

<u>Putting eq 2 and 3 value into eq 1</u>

i.e  AC × CK = 100  

Or, 0.74 d  × 0.66 d = 100  

Or, 0.4884 × d² = 100  

∴ d² = \dfrac{100}{0.4884}

Or, d² = 204.75

Or, d = \sqrt{204.75}

Or, d = 14.30

So, The diameter of circle = d = 14.30 cm

Now, Radius of circle = \dfrac{\textrm diameter}{2}

Or, r =  \dfrac{\textrm 14.30 cm}{2}

i.e r = 7.15 cm

So, The Radius of circle =  r = 7.15 cm

Hence, The Radius of circle is 7.15 cm  Answer

7 0
2 years ago
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