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klemol [59]
3 years ago
10

Solve for x. Round to the nearest tenth of a degree, if necessary

Mathematics
1 answer:
Fynjy0 [20]3 years ago
8 0

Step-by-step explanation:

here's the answer to your question

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What is the greatest common factor of 3x4, 15x3, and 21x??
luda_lava [24]

Answer:

The GCF of 3x^4, 15x^3 and 21x is 3x^2

Step-by-step explanation:

3x^2(x^2), 3x^2(5x) , 3x^2(7)

4 0
3 years ago
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4. JKLM is a parallelogram. Find JM.<br> J<br> к<br> 8x + 4<br> 4x + 20<br> M<br> L
madam [21]

Answer:

36

Step-by-step explanation:

8x + 4 = 4x + 20

8x - 4x = 20 - 4

4x = 16 divide both sides by 4

x = 4 and JM = 8x + 4 replace x with 4

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2 years ago
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Let X denote a random variable which corresponds to the number of players in a team who get injured during a game. If we assume
Feliz [49]

Answer:

(a)

The values of X can be 0, 1, 2 , ..., 10 . So, X is a discrete random variable.

(b)

The distribution of X is Binomial distribution with the parameters n = 10 and p = 0.2

(c)

Probability that no one or one person will be injured = P(X = 0) + P(X = 1)

= 10C0 * 0.20 * (1 - 0.2)10-0 + 10C1 * 0.21 * (1 - 0.2)10-1

= 0.810 + 10 * 0.2 * 0.89

= 0.3758096

(d)

Average value of X = np

Average value of X = 10 * 0.2 = 2

(e)

Variance of X = np(1-p)

Variance of X = 10 * 0.2 * (1 - 0.2) = 1.6

(f)

Number of ways in which 2 people gets injured = 10C2 = 10! / ((10-2)! 2!) = (10 * 9) / (2 * 1) = 45

Assume the best player got injures, number of ways in which one people out of remaining 9 people gets injured = 9C1

= 9! / ((9-1)! 1!)

= 9

Probability that the best player got injured = Number of ways in which 1 people gets out of 9 and best person gets injured / Number of ways in which 2 people gets injured

= 9 / 45

= 0.2

4 0
3 years ago
(x^2y^-2)^3/yx^-4 please help
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Hey is there a way you could send a photo of the equation
3 0
2 years ago
Determine the x-intercepts of the function. Check all that apply. (–2, 0) (–1, –2) (0, 0) (1, 0) (2, 0)
blagie [28]

it's (0, 0) and (-2, 0) so A & C

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3 years ago
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