<span>0.50 mg x ( 1 mL / 0.25 mg ) = 2 mL </span>
Answer:
5.559*10^(23) atoms
Explanation:
Molar Mass of Al(OH)3 = 78 g/mol
(72g/78g/mol)*(6.022*10^(23)atoms/mol) = 5.559*10^(23) atoms in 72 grams of Al(OH)3
Answer:
the independent variable is the beakers
Explanation: