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Maru [420]
3 years ago
8

** 50 POINTS ANSWER FAST PLEASE! ** I need the answers to this worksheet (for extra credit)

Chemistry
1 answer:
nikitadnepr [17]3 years ago
8 0
1. SD
2. S
3. DR
4. D
5. DR
6. SD
7. SD
8. S
9. D
10. DR
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Answer:

Use a ratio of 0.44 mol lactate to 1 mol of lactic acid  

Explanation:

John could prepare a lactate buffer.

He can use the Henderson-Hasselbalch equation to find the acid/base ratio for the buffer.

\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\3.5 = 3.86 + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\\log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 3.5 - 3.86 = -0.36\\\\\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 10^{-0.36} = \mathbf{0.44}

He should use a ratio of 0.44 mol lactate to 1 mol of lactic acid.

For example, he could mix equal volumes of 0.044 mol·L⁻¹ lactate and 0.1 mol·L⁻¹ lactic acid.

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3 years ago
In the reaction 2 H2 + O2m 2 H20, how
Tresset [83]

Answer:

Option F. 3moles

Explanation:

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2H2 + O2 —> 2H2O

from the equation,

2moles of H2 required 1mole of O2.

Therefore, 6moles of H2 will require = 6/2 = 3moles of O2

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