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storchak [24]
3 years ago
14

The axis of symmetry for the function f(x) = -x^2 - 10x + 16 is x = -5. What are the coordinates of the vertex of the graph?

Mathematics
2 answers:
IRINA_888 [86]3 years ago
9 0
The x coordinate is -5.

The y coordinate is equal to f(-5)

f(-5)=-(-5)^2-10\cdot(-5)+16=-25+50+16=41

So the vertex is (-5,41)
max2010maxim [7]3 years ago
7 0

Answer:

(x, f(x))= (-5, 41)

Step-by-step explanation:

Your function is a  parable, then you have the axis of symmetry which is the straight line that divides your graph in half, this is X = -5,

If you replace this value of X in the original equation f(-5)=-(- 5)^2-(10*(-5))+16

you get f(-5)=-(25)+50+16 the result is 41, which is the value on the other axis.

Therefore the coordinates of the parabola vertex are (x, f(x))=(-5,41)

This means the coordinates (vertex) where the function reaches a maximum or minimum value, in this case the maximum.

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The average discharge at the mouth of the Amazon River is 4,900,000 cubic feet per second. How much water is discharged from the
Misha Larkins [42]

Answer:  Average discharge at the mouth of the Amazon River in 1 hour = 1.764\times 10^{10} cubic feet

Average discharge at the mouth of the Amazon River in 1 year= 3.66912\times10^{13} cubic feet[/tex]

Step-by-step explanation:

Given : The average discharge at the mouth of the Amazon River =4,900,000 cubic feet per second.

i.e. The average discharge at the mouth of the Amazon River  in 1 second= 4,900,000 cubic feet

Since 1 hour = 3600 seconds

Then , the average discharge at the mouth of the Amazon River  in 1 hour =

4900000\times3600=17640000000 cubic feet

Since , there are 2080 hours in a typical year.

Then, the average discharge at the mouth of the Amazon River in 1 year=

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6 0
2 years ago
Can somebody please help me? I will mark brainiest if i can!<br> qr + r; use q = 3, and r = -6
Sveta_85 [38]
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3 0
3 years ago
Find the distance between the point - 3, 2 and 1 - 1​
dusya [7]

Answer:

5 units

Step-by-step explanation:

Find the distance between the point - 3, 2 and 1 - 1​

Given data

x1= -3

y1= 2

x2= 1

y2= -1

The expression for the distance between two points is

d=√((x_2-x_1)²+(y_2-y_1)²)

subtitute

d=√((1-(-3))²+(-1-(2))²)

d=√((1+3))²+(-1-2))²)

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Hence the distance between the points is 5 units

7 0
2 years ago
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