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2 years ago

HELP ME NOW PLS ITS PYTHAGOREAN THEOREM IM FAILING THIS PLS PLS PLS :(

Mathematics

2 answers:

Savatey [412]2 years ago

7 0

Answer:

Step-by-step explanation:

Add the numbers and then boom answer (i think and hope)

Zina [86]2 years ago

4 0

Answer:

7.8 miles

Step-by-step explanation:

The game store is 6 miles south = a side

The skate park is 5 miles east = b side

We’re trying to find the straight-line distance (side c) between the school and the skate park

a^2 + b^2 = c^2

6^2 + 5^2 = c^2

36 + 25 = c^2

c^2 = 61

c^2 (sqrt rt) = 7.8

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Please Answer Attachment Below Thanks

docker41 [41]

Answer:

Step-by-step explanation:

The interior angles of a heptagon add up to 5*180 = 900

x + 143 + 116 + 135 + 135 + 116 + 155 = 900 Add up the known angles

x + 800 = 900 Subtract 800 from both sides

x + 800 - 800 = 900 - 800 Combine

x = 100

8 0

3 years ago

On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite direction. The numb

vfiekz [6]

Answer:

Step-by-step explanation:

5 0

3 years ago

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago

Five sixths of Forty two

Maslowich

Hello,

Five sixths of forty two is = 35.

7 0

2 years ago

A deep-sea diver dived off a boat to a depth of -45 feet. What is the absolute value that expresses the distance the diver went?

Vlad1618 [11]

45 feet.

Absolute value is the distance of a number from 0. Say 0 is the surface of the ocean, then the diver is 45 feet away from it. Either from above or below, they are the same distance away.

7 0

2 years ago