assuming you means k = log_2(3) [as log(2)3 is the same thing as 3log(2) due to multiplication being commutative]
given log(ab) = log(a) + log(b)
log_2(48) = log_2(3) + log_2(16)
A. Let x = cheese and
y = chocolate
2x + y = 25
x + y = 20
B. Subtract the second equation from the first.
2x + y = 25
-(x + y = 20)
-—————
x = 5
Plug 5 back in to the second equation and solve for y.
x + y = 20
5 + y = 20
Subtract 5 from both sides.
y = 15
5 cheese and 15 chocolate
Used elimination method because coefficients on the y values were both 1 so it was easy to subtract the equations and eliminate the y variable.
Answer:
11
Step-by-step explanation:
Given that in a sample of n=6, five individuals all have scores of X=10 and the sixth person has a score of x=16
i.e. the data entries are
10,10,10,10,10,16
Sum = 66
No of items n = 6
Average = sum/no of entries
=
Average is 11.
mean of this sample is 11
Answer:
The number is 16
Step-by-step explanation:
3/4 n- (-16) = 28
3/4 n + 16 = 28
Subtract 16 from each side
3/4 n +16-16 = 28-16
3/4 n =12
Multiply by 4/3 to isolate n
4/3 * 3/4 n = 12 * 4/3
n = 16
Answer:
30p^3−36p
Step-by-step explanation:
6(5p^3−6p)
=(6)(5p^3+−6p)
=(6)(5p^3)+(6)(−6p)
=30p3−36p
