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3 years ago

PLEASE ANSWER ASAP!!! CORRECT ANSWERS PLEASE!!!

Mathematics

1 answer:

kozerog [31]3 years ago

3 0

The answer is the second choice. Hope that was helpful

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Felicia invested $25,000 into an account earning 3% interest compounded annually. She makes no other deposits into the account a

rewona [7]

The formula is
A=p (1+r)^t
A future value?
P present value 25000
R interest rate 0.03
T time 9 years
A=25,000×(1+0.03)^(9)
A=32,619.33

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4 years ago

Forty-three girls went camping. The girls were able to choose to participate in karate and swimming. Twenty-one girls went swimm

horsena [70]

7 girls participated only in Karate.
21 + 8 = 29
29 + 7 = 36
36 + 6 = 43

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3 years ago

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Which is a factor of x2 - 9x + 14?<br> O X-9<br> O X-2<br> O x + 5<br> O x + 7

Vinil7 [7]

(X-7) and (x-2)
Factor x2 -9x+ 15 using the AC method

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3 years ago

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What will the coordinate K(3, - 3) be after the translation 8 units to the left and 7 units up.

natita [175]

Answer:

(-5, 4)

Step-by-step explanation:

To find the new coordinate, subtract 8 from the x value and add 7 to the y value:

3 - 8 = -5

-5 will be the new x coordinate

-3 + 7 = 4

4 will be the new y coordinate

So, the coordinate K will be (-5, 4) after the translation

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3 years ago

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A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple. How many ways are there to choose:(

Volgvan

Answer:

The number of ways of selecting of n items form r different items = $^{(n+r-1)}C_{(r-1)}$

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple.

A) How many ways are there to choose 32 candies?

So, n = no. of items = 32

r = no. of types of items = 5

So, No. of ways to choose 32 candies = $^{(32+5-1)}C_{(5-1)}$

= $^{36}C_{4}$

= $\frac{36!}{4!(36-4)!}$

= $58905$

So, No. of ways to choose 32 candies is 58905

B)32 candies with at least a piece of each flavor?

Out of 32 you choose 5 candies of different types

So, Remaining candies = 32 - 5 = 27

So, No. of ways to choose 27 candies = $^{(27+5-1)}C_{(5-1)}$

= $^{31}C_{4}$

= $\frac{31!}{4!(31-4)!}$

= $31465$

So, No. of ways to choose 32 candies with at least a piece of each flavor is 31465

C) 32 candies with at least 4 cherry and at least 6 lemon?

So, you already choose 6+4= 10

So, remaining candies = 32-10 = 22

So, No. of ways to choose 22 candies = $^{(22+5-1)}C_{(5-1)}$

= $^{26}C_{4}$

= $\frac{26!}{4!(26-4)!}$

= $14950$

Hence No. of ways to choose 32 candies with at least 4 cherry and at least 6 lemon is 14950

8 0

4 years ago