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3 years ago

11

The table shows how a leading automobile dealer plans to spend its advertising dollars for this year. If this company plans to i

ncrease its budget by 5% next year, approximately how much will it spend on social media ads?

1 answer:

andrew-mc [135]3 years ago

3 0

$425 is the awnser for this one have a great day

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An online furniture store sells chairs for $200 each and tables for $450 each. Every day, the store can ship a maximum of 26 pie

Sophie [7]

Answer:

its 10

Step-by-step explanation:

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3 years ago

In the diagram, which two angles are alternate interior angles with angle 14?

Nookie1986 [14]

I agreed Angle 4 and 12 is the right answer

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3 years ago

Please help! i don’t understand this question thank youuuu

ad-work [718]

Can i see it with the drop menus down

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3 years ago

Read 2 more answers

A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)

Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

$36^6$

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

$5\cdot 36^5$

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

$\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}$

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

$P(A)=P(B)=\dfrac{5}{36}$

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

$axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8$

$exxxx0,\ exxxx2,\ exxxx4,\ exxxx6,\ exxxx8$

$ixxxx0,\ ixxxx2,\ ixxxx4,\ ixxxx6,\ ixxxx8$

$oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8$

$uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8$

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

$P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}$

Finally, you can compute the probability of the union using the formula

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Since we already computed all these quantities.

7 0

2 years ago

Adding or subtracting fractions with different denominators

Bas_tet [7]

Step-by-step explanation: You can't continue on with the problem until the denominators are the same. So you need to find the LCD (Least Common Denominator). For example...

$\frac{1}{2} +\frac{1}{3}$ The LCD is six

$\frac{1*3}{2*3}=\frac{3}{6} =\frac{1}{3}$

$\frac{1}{2}+ \frac{1}{3}= \frac{3}{6} +\frac{2}{6}$

$\frac{3+2}{6}= \frac{5}{6}$

Hope this helps, have a BLESSED and wonderful day! :-)

-Cutiepatutie <3

8 0

3 years ago