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koban [17]
4 years ago
12

What is 9^3 multiplied by 11^4

Mathematics
1 answer:
Leya [2.2K]4 years ago
7 0

Answer:

\displaystyle 10673289

Step-by-step explanation:

Order of operations

PEMDAS

<em>P- Parenthesis, E-Exponent, M-Multiply, D-Divide, A-Add, and S-Subtract.</em>

<em>Do exponent.</em>

<em>\displaystyle 9^3=9*9*9=729</em>

<em>11^4*729</em>

<em>11^4=11*11*11*11=14641</em>

<em>14641*729</em>

<em>Multiply from left to right.</em>

<em>14641*729=10673289</em>

<em>10673289 is the correct answer.</em>

<em>Hope this helps!</em>

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The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 104 inches, and a standard
dsp73

Answer:

91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

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Z = \frac{X - \mu}{\sigma}

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Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 104, \sigma = 14, n = 49, s = \frac{14}{\sqrt{49}} = 2

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This is the pvalue of Z when X = 106.8. So

Z = \frac{X - \mu}{\sigma}

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Z = 1.4 has a pvalue of 0.9192

0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

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