standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient


Answer:
Step-by-step explanation:
The first composite shape is a combination of a rectangular prism and a pyramid. To find the volume of the entire shape you find the volume of each individual shape and add them together. The second figure consists of a cylinder and a hemisphere.
Answer:
it's part of the real number system
it's a rational number
it's an integer
Step-by-step explanation:
Answer:
1.
2.543.6
Step-by-step explanation:
We are given that
y(0)=200
Let y be the number of bacteria at any time
=Number of bacteria per unit time


Where k=Proportionality constant
2.
,y'(0)=100
Integrating on both sides then, we get

We have y(0)=200
Substitute the values then , we get


Substitute the value of C then we get





Differentiate w.r.t

Substitute the given condition then, we get



Substitute t=2
Then, we get 

e=2.718
Hence, the number of bacteria after 2 hours=543.6