Answer:
x = 18 or x = -12.
Step-by-step explanation:
||x-3|-5| = 10 only if |x-3|-5 = 10 or |x-3|-5 = -10, i.e., if |x-3|=15 or |x-3|=-5; but |x-3| cannot be equal to -5, because |x-3| should be a non-negative value. Therefore, the first equation is true only if |x-3|=15. |x-3| = 15 only if x-3 = 15 or x-3 = -15, i.e., x = 18 or x = -12. We can verify this in the following way: ||18-3|-5|=||15|-5|=|10|=10 and ||-12-3|-5|=||-15|-5|=|15-5|=|10|=10. This verify that our solution is correct.
Answer:
The graph approaches –3 as x approaches infinity. Option a is correct.
Step-by-step explanation:
The given function is

We have to find value of function as x approaches infinity. Take limit both sides as x approaches to infinity.

Taking x common from the denominator.

Cancel out common factor x.

Apply limits.



Therefore the graph approaches –3 as x approaches infinity.
= 9a(5x² + 3x + 2)
The distributive property lets you remove the same factor from all terms and write it outside parentheses.